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Alik [6]
2 years ago
14

Use Newton's method with initial approximation x1 = −2 to find x2, the second approximation to the root of the equation x3 + x +

7 = 0. (Round your answer to four decimal places.)
Mathematics
1 answer:
nevsk [136]2 years ago
5 0

Answer:

x_2 \approx -1.769

Step-by-step explanation:

Let f(x)=x^3+x+7

So f'(x)=3x^2+1

x_{n+1}=x_n-\frac{f(x_n)}{f'(x_n)}

Let x_1=-2

We are going to find x_2

So we are evaluating -2-\frac{f(-2)}{f'(-2)}

First step find f(-2)

Second step find f'(-2)

Third step plug in those values and apply PEMDAS!

f(-2)=(-2)^3+(-2)+7=-8-2+7=-10+7=-3

f'(-2)=3(-2)^2+1=3(4)+1=12+1=13

So

x_2=-2-\frac{-3}{13} \\\\ x_2=\frac{-26+3}{13} \\\\ x_2=\frac{-23}{13} \\\\ x_2 \approx -1.769

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lions [1.4K]

Answer:

Length of KS = 25 units and

Length of KP = 17 units.

Step-by-step explanation:

Given: KPST is a trapezoid, KP =ST, MN is a mid segment, h is the height =15

Also it is given that, MN = 20 , h = 15 and PS:KT = 3:7.

  • If two sides of the trapezoid are equal then, it is an isosceles trapezoid.
  • Mid-segment of a trapezoid is a line segment which connects the midpoints of the non-parallel sides.
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Since, the length of Mid-segment MN = 20.

Also, it is given: PS:KT = 3:7

Let  PS = 3x and KT = 7x respectively.

then;

\frac{PS+KT}{2} = 20

\frac{3x+7x}{2} = 20

\frac{10x}{2} =20

On Simplify, we get;

5x =20

Divide both sides by 5 we get;

x =4

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Length of base PS = 3x = 3(4) = 12 and Length of base KT = 7x = 7(4) = 28.

Now, In triangle PLK

Using Pythagoras theorem to find KP;

It is given here, PL =h =15 and KL= 8 {you can see in the figure as shown below};

KP^2= PL^2 + KL^2

KP^2 = 15^2+8^2 =225 +64 = 289

KP = \sqrt{289}

Simplify:

KP = 17

therefore, the length KP = 17 units

To, construct a line: Join K and S

Now, in triangle KRS

KR = KL +LR = 8 +12 =20 and SR = h= 15

Using Pythagoras theorem in KRS to find KS;

KS^2 = SR^2+KR^2

KS^2 = 15^2 + 20^2 = 225 + 400 = 625

KS = \sqrt{625}

On simplify:

KS = 25

Therefore, the length of KS is, 25 units.

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