Answer:
see below
Step-by-step explanation:
The graph extends to the left more or less horizontally, approaching the line y=3. The only choice that expresses that is the third one.
I find it easiest to use slope-intercept form, or y=mx+b, to do this.
First, find the slope. 6/3 = 2/1 = 2. m = 2.
Next, find the y-intercept. In this case they gave it to you directly. b = -3.
So, the equation would be y = 2x - 3.
Since there are more parakeets than canaries, it is not possible to have only 1 of each bird in each cage <u>and</u> have the same number of birds in each cage.
He could use 42 cages, putting a canary in with the parakeet in 18 of them. Then he would have 18 cages with 2 birds each, and 24 cages with 1 bird each.
The only way to have the same number of birds (1) in all cages is to have 60 cages, 42 of which have 1 parakeet, and 18 of which have 1 canary.
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If more than 1 of each kind of bird can be put in the cage, the collection of birds could be put into 6 cages, each of which would be home to 7 parakeets and 3 canaries.
Answer:
Simply count 4 × 6 =28
Step-by-step explanation:
