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luda_lava [24]
3 years ago
11

Can you guys pls help me out

Mathematics
2 answers:
34kurt3 years ago
8 0

Answer:

answer C

i think

hope this helps

steposvetlana [31]3 years ago
5 0

Answer:

i think the answer is D It took for ever just to find this pls brainlist me ?!

Step-by-step explanation:

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1/2x + 5y- 10< 0 The point (4,y) is a solution for the inequality shown. What is the value for y.
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Subtract x on both sides the result you divide it by 5
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Your race car weighs 1.5 tons. To make the car faster, you replaced the steel body with carbon-fiber and reduced the weight by 3
Scorpion4ik [409]
One ton = 2000 lbs
Therefore, 1.5 tons = 3000 lbs
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3 years ago
Mary spent half of her allowance going to the movies. She washed the family car and earned seven dollars. What is her weekly all
Nata [24]

Answer:If Mary spent half of her allowance the equation will begin with 1/2x or 0.5x where x is her allowance and 0.5 is half of her allowance spent. Mary also earned 7 dollars by washing the car so this will be added to her allowance spent.

The problem says that after Mary has spent half of her allowance at the movies she was left with 18 dollars so that means that the equation must be equal to 18.

The equation you want to set up is

0.5x+7=18

Where, 18-7=11

0.5x=11

11/.5 = x

x = $22

Thus, Mary has a weekly allowance of 22 dollars.

Step-by-step explanation:

4 0
3 years ago
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NO LINKS!!!<br><br>14. Consider the table​
iVinArrow [24]

Answer:

(a) rate of change = 8

(b) Function: y = 8x

(c) Domain: 0 ≤ x ≤ 2

    Range: 0 ≤ y ≤ 16

Explanation:

Looks like a inverse variation sequence.

Inverse Variation formula: y = k(x)

Take two points: (1, 8), (2, 16)

Find the value of k which is constant also considered as <u>rate of change</u>.

<u>Insert values</u>:

  • 8 = k(1)
  • k = 8

===========

  • 16 = k(2)
  • k = 8

Equation: y = 8x

Domain lies in the x axis, Range lies in the y axis.

  • Here domain: 0 ≤ x ≤ 2
  • Here range: 0 ≤ y ≤ 16
5 0
2 years ago
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In most microcomputers the addresses of memory locations are specified in hexadecimal. These addresses are sequential numbers th
iren [92.7K]

Considering that the addresses of memory locations are specified in hexadecimal.

a) The number of memory locations in a memory address range ( 0000₁₆ to FFFF₁₆ )  = 65536 memory locations

b) The range of hex addresses in a microcomputer with 4096 memory locations is ;  4095

<u>applying the given data </u>:

a) first step : convert FFFF₁₆ to decimal           ( note F₁₆ = 15 decimal )

( F * 16^3 ) + ( F * 16^2 ) + ( F * 16^1 ) + ( F * 16^0 )

= ( 15 * 16^3 ) + ( 15 * 16^2 ) + ( 15 * 16^1 ) + ( 15 * 1 )

=  61440 + 3840 + 240 + 15 = 65535

∴ the memory locations from  0000₁₆ to FFFF₁₆ = from 0 to 65535 = 65536 locations

b) The range of hex addresses with a memory location of 4096

= 0000₁₆ to FFFF₁₆ =  0 to 4096

∴ the range = 4095

Hence we can conclude that the memory locations in ( a ) = 65536 while the range of hex addresses with a memory location of 4096 = 4095.

Learn more : brainly.com/question/18993173

6 0
3 years ago
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