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dangina [55]
4 years ago
5

The current size of an image on Sandra's computer is shown below:

Mathematics
2 answers:
Verdich [7]4 years ago
6 0

Answer:

Option B is correct

Length = 3 inches, width = 4 inches

Step-by-step explanation:

As per the statement:

The current size of an image on Sandra's computer is shown below:

A rectangle is shown:

The length of the rectangle is labeled as length equal to 6 inches and the width is labeled as width equal to 8 inches.

⇒Length(l) = 6 inches and width(w) = 8 inches

We have to find the dimension of the image at fraction 1 over 2 times its current size.

Dimensions of the image at \frac{1}{2} \times \text{Current Size}

then;

\text{Length} = \frac{1}{2} \times \text{Current size of length}=\frac{1}{2} \times 6 =3 inches

and

\text{Width} = \frac{1}{2} \times \text{Current size of width}=\frac{1}{2} \times 8 =4 inches

Therefore, the dimensions of the image at fraction 1 over 2 times its current size are:

Length = 3 inches, width = 4 inches

Radda [10]4 years ago
5 0
6*1/2=3
8*1/2=4
Length= 3 inches
width= 4 inches
Answer : B
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You can work out c first. That's probably the key to the whole problem.
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Next work out a.
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