Answer:
Amount invested that yielded interest of 5% is $15000 and amount invested that yielded interest of 8% is $5000
Step-by-step explanation:
Johnny invested $20,000
We are told that it consisted of 2 portions because one returned an interest of 5% and the other one 8%
Now, Let x be the amount invested that earned 5% and y be the amount invested that earned 8%
Thus:
x + y = 20000 - - - (eq 1)
The total interest earned on the investment was $1150
Thus;
5%x + 8%y = 1150
This can be rewritten as;
0.05x + 0.08y = 1150 - - -(eq 2)
From eq 1, let's make x the subject.
x = 20000 - y
Putting 20000 - y for x in eq 2 gives;
0.05(20000 - y) + 0.08y = 1150
1000 - 0.05y + 0.08y = 1150
Rearranging, we have;
0.03y = 1150 - 1000
0.03y = 150
y = 150/0.03
y = 5000
Thus,
x = 20000 - 5000
x = 15000
Thus,
Amount invested that yielded 5% is $15000 and amount invested that yielded 8% is $5000
Answer:
X=2
Step-by-step explanation:
3X+8 = 4X+6
3(2)+8=14.......4(2)+6=14
Answer is 182. Just substitute the x and y value into the equation.
Answer:
the y intercept is 4
Step-by-step explanation:
f(x)=4-5x
rewrite
y = -5x+4
this is in the form y= mx+b where b is the y intercept
b = 4
