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3 years ago

11

Help plz im stuck on this

1 answer:

german3 years ago

8 0

Answer:

13 cm

Step-by-step explanation:

AC=BD=13 cm

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One student begins in Cleveland, Ohio, and walks towards Buffalo, New York, a distance of 200 miles. She walks at the rate of 2.

omeli [17]

Ok so student in cleveland walks 2.5 miles away from cleveland every hour from 8
so the distance, x is x=2.5t

the riding one rides 4 hours later, so t-4
11 mph
y=11(t-4)

A. x=2.5t
y=11(t-4)

when do they meet is when the distance when they are equal or when x=y
2.5t=x=y=11(t-4)
solve for t
2.5t=11(t-4)
2.5t=11t-44
-8.5t=-44
divide both sides by -8.5
t=5.17647

answer is 5.18 hours

A.
x=2.5t
y=11(t-4)

B. 5.18 hours

6 0

3 years ago

If g(x) = 5x2^2 - 10x + 9 and h(x) = -3x3^3+ 5x - 6, find g(x) - h(x)?

AnnZ [28]

Answer:

B) $g(x) - h(x) = 3x^3 - 5x^2 - 15x + 15$

Step-by-step explanation:

Here, the given functions are:

$g(x) = 5x^2- 10x + 9 \\h(x) = -3x^3+ 5x - 6$

Now, g(x) - h(x) is :

$(5x^2- 10x + 9) - ( -3x^3+ 5x - 6)\\= 5x^2- 10x + 9 + 3x^3 - 5x + 6\\= 3x ^3 + 5x ^2+ (-10 x - 5 x) + (9 + 6)\\= 3x^3 - 5x^2 - 15x + 15$

⇒ $(5x^2- 10x + 9) - ( -3x^3+ 5x - 6) = 3x^3 - 5x^2 - 15x + 15$

B) Hence, $g(x) - h(x) = 3x^3 - 5x^2 - 15x + 15$

3 0

3 years ago

25 POINTS! MATCHING PROBLEM!

Nataly_w [17]

1. f(x) = 1
2. f(x) = x
3. f(x) = 5 - x
4. f(x) = 3

8 0

3 years ago

Please solve this...question..it may come in my exam.#math problem fast solve it and help me

ehidna [41]

Answer:

n + y

Step-by-step explanation:

a² - b² = (a +b)(a - b)

$\frac{n^{2}-y^{2}}{n+y}$ ÷ $\frac{n - y }{n + y } = \frac{(n + y)(n - y)}{(n + y)}*\frac{(n + y)}{(n - y)}\\\\$

{ (n + y) in the denominator and numerator will be cancelled ;

(n - y) in the denominator and numerator will be cancelled

= n + y

3 0

3 years ago

The recursive rule for a sequence is shown.an=an−1+9a1=21 what is the explicit rule for this sequence?

bixtya [17]

Answer:

Meaning of Explicit rule , is the general rule for a sequence.

The given sequence is defined as,

$a_{n}=a_{n-1}+9a_{1}-21$ ----(1)

Common Difference(d) of an airthmetic Sequence= N th term - (N-1) th term

$=a_{n}-a_{n-1}\\\\=a_{n-1}-a_{n-2}$

Equation 1 can be written as,

$a_{n}-a_{n-1}=9 a_{1}-21\\\\ d =9a_{1}-21$

General rule or explicit rule for this sequence is given as:

$a_{n}=a_{1} +(n-1)d\\\\a_{n}=a_{1}+(n-1)(9a_{1}-21)\\\\a_{n}=a_{1}+9na_{1}-21 n-9a_{1}+21\\\\a_{n}=-8a_{1}+21+n(9a_{1}-21)$

6 0

3 years ago