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Answer:
The equation of line 3 is;
y = + 6
Step-by-step explanation:
Line 1 passes through the points A(-15,-8) andn B(-3,0)
Line 2 has equation shown below;
5x - 3y + 18 = 0
Line 3 is parallel to line 1 and has the same y-intercept as line 2.
We are to determine the equation of line 3.
<u>Equation of line 1:</u>
<u />
Slope = change in y-axis ÷ change in x-axis
The slope of line 1 =
Picking another point (x,y) on the line;
Slope =
y = + 2 (this is the equation of line 1)
<u>Equation of line 2:</u>
<u />
We put the equation given, of line 2, in the cartesian plane format;
3y = 5x + 18
y = + 6
Finally, the equation of line 2 is;
y = 1 + 6
<u>Equation of line 3:</u>
<u />
Given: Line 3 is parallel to line 1
The slopes of two parallel lines are the same so line 3 has a slope of
Given: Line 3 has the same y-intercept as line 2
The y-intecept of line 2 is 6 (y-intercept is the value of y when x = 0)
So the equation of line 3 is;
y = + 6
Answer:
Step-by-step explanation:
Sinθ =
If, sinθ = - and π < θ <
Since, sinθ is negative, angle θ will be in IIIrd quadrant.
And the measure of angle θ will be (180° + 30°)
θ = 210°
It's necessary to remember that tangent and cotangent of angle θ in quadrant III are positive.
Therefore, cos(210°) =
tan(210°) =
csc(210°) =
sec(210°) =
cot(210°) = √3