Answer:
1: SSS
2: SAS
3: SSS
4: SSS
5: SAS
6: SSS
Step-by-step explanation:
<span>If you plug in 0, you get the indeterminate form 0/0. You can, therefore, apply L'Hopital's Rule to get the limit as h approaches 0 of e^(2+h),
which is just e^2.
</span><span><span><span>[e^(<span>2+h) </span></span>− <span>e^2]/</span></span>h </span>= [<span><span><span>e^2</span>(<span>e^h</span>−1)]/</span>h
</span><span>so in the limit, as h goes to 0, you'll notice that the numerator and denominator each go to zero (e^h goes to 1, and so e^h-1 goes to zero). This means the form is 'indeterminate' (here, 0/0), so we may use L'Hoptial's rule:
</span><span>
=<span>e^2</span></span>
Your distance from Seattle after two hours of driving at 62 mph, from a starting point 38 miles east of Seattle, will be (38 + [62 mph][2 hr] ) miles, or 162 miles (east).
Your friend will be (20 + [65 mph][2 hrs] ) miles, or 150 miles south of Seattle.
Comparing 162 miles and 150 miles, we see that you will be further from Seattle than your friend after 2 hours.
After how many hours will you and your friend be the same distance from Seattle? Equate 20 + [65 mph]t to 38 + [62 mph]t and solve the resulting equation for time, t:
20 + [65 mph]t = 38 + [62 mph]t
Subtract [62 mph]t from both sides of this equation, obtaining:
20 + [3 mph]t = 38. Then [3 mph]t = 18, and t = 6 hours.
You and your friend will be the same distance from Seattle (but in different directions) after 6 hours.
Answer:
3
Step-by-step explanation:
you have 12 dollars left. divided by 4, is 3 hours
Y = 3/2x + b
4 = 3/2(-10) + b
4 = -15 + b, b = 19
Y = 3/2x + 19
