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kupik [55]
3 years ago
15

Joe left the park to go home at 5:00 pm. He was traveling east at 15 mph. Two hours later, Mark left the park heading east to tr

y to catch up with Joe because Joe had forgotten his skateboard at the park. Mark travels at a rate of 25 mph. How long will it take Mark to catch up with Joe?
Equation to solve the problem:

Amount of time for Mark to catch up with Joe:
Mathematics
1 answer:
Alexxx [7]3 years ago
6 0
15 more miles to catch up with joe
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I WILL GIVE 20 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT NOOOO SCAMS PLEASE AND PLEASE EXPLAIN WHY THAT IS THE ANSWER
nekit [7.7K]

Answer:

1 - 60

2 - 120

3 - 60

4 - 120

5 - 60

6 - 120

7 - 60

8 - 120

Step-by-step explanation:

Via supplementary angles, you can conclude that angle 5 is 60. Because of vertical angles, angle 8 is 120 and angle 7 is 60. Because of alternate exterior angles, angle 1 is congruent to angle 7 and angle 2 is congruent to angle 8, meaning angle 1 is 60 and angle 2 is 120. Because of vertical angles, angle 3 is 60 and angle 4 is 120.

7 0
2 years ago
An integer N is to be selected at random from {1, 2, ... , (10)3 } in the sense that each integer has the same probability of be
Andrej [43]

Answer:

Probability of N Divisible by 3 - 0.33

Probability of N Divisible by 5 - 0.2

Probability of N Divisible by 7 - 0.413

Probability of N Divisible by 15 - 0.066

Probability of N Divisible by 105 - 0.0095

Step-by-step explanation:

Given data:

Integer N {1,2,.....10^3}

Thus total number of ways by which 1000 is divisible by 3 i.e. 1000/3 = 333.3

Probability of N divisible by 3 {N%3 = 0 } = \frac{333.3}{1000} = 0.33

total number of ways by which 1000 is divisible by 5 i.e. 1000/5 = 200

Probability of N divisible by 5 {N%5 = 0 } = \frac{200}{1000} = 0.2

total number of ways by which 1000 is divisible by 7 i.e. 1000/7 = 142.857

Probability of N divisible by 7 {N%7 = 0 } = \frac{142.857}{1000} = 0.413

total number of ways by which 1000 is divisible by 15 i.e. 1000/15 = 66.667

Probability of N divisible by 15 {N%15 = 0 } = \frac{66.667}{1000} = 0.066

total number of ways by which 1000 is divisible by 105 i.e. 1000/105 = 9.52

Probability of N divisible by 105 {N%105 = 0 } = \frac{9.52}{1000} = 0.0095

similarly for N is selected from 1,2.....(10)^k where K is  large then the N value. Therefore effect of k will remain same as previous part.

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Please help me worth a bunch of points 26 points
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