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3 years ago

The question is in my screenshot I took. :) Need help, please.

Mathematics

2 answers:

leonid [27]3 years ago

4 0

I am thinking that c is correct and i am truely sorry if u get it wrong

Helen [10]3 years ago

4 0

The answer is C bc there are 3 whole shapes and there divided into 1/3 each

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Find S15 for the series -1 + -3 + -5 + -7 +...

Ber [7]

Hello :
the sum is arithmetic secquence of common -diff is :
(-7)-(-5) =(-5)-(-3) = (-3)-(-1) =-2 = d
the first term is : a1 = -1
the formula of the sum : S= (n/2)(a1 +an)
n is number of term an = a1+(n-1)d

8 0

3 years ago

Simplify the expression. (6)8 + (6)3

Drupady [299]

Answer:

Step-by-step explanation:

Use the PEMDAS order. Multiplication comes before addition so it simplifies to 6(8)+(6)3

=48+18

=66

5 0

3 years ago

Read 2 more answers

Suppose that the function

Dafna11 [192]

Answer:

(f-g)(x)= -3x^3 + x^2 + 6x

(f+g)(×)= 3x^3 + x^2 + 6x

(f•g)(2)= 6x^3 + 36x^3

Step-by-step explanation:

I hope that helps

5 0

2 years ago

How do you simplify expressions with rational exponents

Rainbow [258]

Answer:

Step-by-step explanation:

Simplify expression with rational exponents can look like a huge thing when you first see them with those fractions sitting up there in the exponent but let's remember our properties for dealing with exponents. We can apply those with fractions as well.

Examples

(a) $(p^4)^{\dfrac{3}{2}}$

From above, we have a power to a power, so, we can think of multiplying the exponents.

i.e.

$(p^{^ {\dfrac{4}{1}}})^{\dfrac{3}{2}}$

$(p^{^ {\dfrac{12}{2}}})$

Let's recall that when we are dealing with exponents that are fractions, we can simplify them just like normal fractions.

SO;

$(p^{^ {\dfrac{12}{2}}})$

$= (p^{ 6})$

Let's take a look at another example

$\Bigg (27x^{^\Big{6}} \Bigg) ^{{\dfrac{5}{3}}}$

Here, we apply the $\dfrac{5}{3}$ to both 27 and $x^6$

$= \Bigg (27^{{\dfrac{5}{3}}} \times x^\Big{\dfrac{6}{1}\times {{\dfrac{5}{3}}} }\Bigg)$

$= \Bigg (27^{{\dfrac{5}{3}}} \times x^\Big{\dfrac{2}{1}\times {{\dfrac{5}{1}}} }\Bigg)$

Let us recall that in the rational exponent, the denominator is the root and the numerator is the exponent of such a particular number.

∴

$= \Bigg (\sqrt[3]{27}^{5} \times x^{10} }\Bigg)$

$= \Bigg (3^{5} \times x^{10} }\Bigg)$

$= 249x^{10}$

8 0

2 years ago

All currently has $25. He is going to start saving $5 every week

sergij07 [2.7K]

Answer:

I believe the answer is b

Step-by-step explanation: I think the answer is b because he gets $5 every week and he already has $25 the only thing we dont know is the weeks and you multiply 5 by the weeks so, 5(how much he gets each week) times x (The amount of weeks) plus 25(the amount he already has) equals y(the amount of everything put together)

5 0

3 years ago