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Solnce55 [7]
4 years ago
10

Describe some of the effects that dilated blood vessels will have on blood pressure.

Biology
1 answer:
grin007 [14]4 years ago
7 0
Since pressure is force per unit area, blood pressure could be thought as the force exerted by the blood to the surface area of your blood vessels. When your blood vessels dilate, it means that they expanded. The result would be faster flow of blood. When this happens, the force of the blood is not any more concentrated on your blood vessels because there is more room available. 

Think of a faucet where tap water flows. When you stopper the faucet with your finger, you feel the force of the water. The pressure builds up as manifested by the sound your faucet makes. But when you release your finger, the water rushes through and flows faster. The pressure is released. Therefore, when your blood vessels are dilated, your blood pressure decreases.
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In cats, curled ears result from an allele, Cu, that is dominant over an allele cu, for normal ears. Black color results from an
just olya [345]

Answer:

Explanation:

Cross : ggCuCu X GGcucu --------Parents

F1 progeny : GgCucu

Two of the F1 cats mate :

Cross : GgCucu X GgCucu

Gametes :

Gg X Gg = GG, Gg, Gg, gg

Cucu X Cucu = CuCu, Cucu, Cucu, cucu

1/4 GG X 1/4 CuCu = 1/16 GGCuCu (black - curled ears)

1/4 GG X 2/4 Cucu = 2/16 GGCucu (black - curled ears)

1/4 GG X 1/4 cucu = 1/16 GGcucu (black - normal ears)

2/4 Gg X 1/4 CuCu = 2/16 GgCuCu (black - curled ears)

2/4 Gg X 2/4 Cucu = 4/16 GgCucu (black - curled ears)

2/4 Gg X 1/4 cucu = 2/16 Ggcucu (black - normal ears)

1/4 gg X 1/4 CuCu = 1/16 ggCuCu (gray - curled ears)

1/4 gg X 2/4 Cucu = 2/16 ggCucu (gray - curled ears)

1/4 gg X 1/4 cucu = 1/16 ggcucu (gray - normal ears)

Answer : (i). 9/16 black cats, curled ears; 3/16 black cats, normal ears; 3/16 gray cats, curled ears; and 1/16 gray cats, normal ears.

An F1 cat mates with a stray cat that is gray and possesses normal ears :

Cross : GgCucu X ggcucu

Gametes :

Gg X gg = Gg, Gg, gg, gg

Cucu X cucu = Cucu, Cucu, cucu, cucu

2/4 Gg X 2/4 Cucu = 4/16 GgCucu (black - curled ears)

2/4 Gg X 2/4 cucu = 4/16 Ggcucu (black - normal ears)

2/4 gg X 2/4 Cucu = 4/16 ggCucu (gray - curled ears)

2/4 gg X 2/4 cucu = 4/16 ggcucu (gray - normal ears)

Answer : (i). 1/4 black cats, curled ears; 1/4 black cats, normal ears; 1/4 gray cats, curled ears; 1/4 gray cats, normal ears.

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3. How are frog eggs being used in research involving human cells?
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Frog cool so that’s basically why
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What does the substance of O and H represent?
Zarrin [17]

Answer:

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Explanation:

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A teacher is demonstrating that the boiling point of water does not change with water volume.
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Answer:

heat 100ml and 300 ml of water and record the temperature when boiling occurs

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Which of the following is most similar in structure to ATP?
Elanso [62]
<h2>The correct answer is : C) an RNA nucleotide.</h2>

Explanation:

  • Nucleic acids, DNA or deoxyribonucleic acid and RNA or Ribonucleic acid are the biological macro-molecules formed by the polymerization of monomeric units called Deoxy-ribonuclotide and Ribonucleotide respectively.
  • Each nucleotide or deoxy-ribonucleotide is comprised of:
  1. A pentose sugar, deoxyribose for DNA and ribose for RNA. The Ribose has a hydroxyl group at the 2' carbon position of the sugar molecule. This hydroxyl group is replaced by hydrogen in the deoxyribose sugar.
  2. A nitrogenous base, like adenine, guanine, cytosine and thymine (for DNA) and uracil (for RNA) linked to the 1' carbon of the deoxyribose or ribose sugar through glycosidic linkage.
  3. One phosphate group which forms a phosphodiester bond in between the 3' carbon of one sugar molecule with the 5' carbon of the next sugar molecule in the nucleic acid polymer.
  • An ATP molecule contain:
  1. Ribose as the pentose sugar but not deoxyribose.
  2. The nitrogenous base here is Adenine.
  3. Three phosphate groups, alpha, beta and gamma, linked to each other by two phospho-anhydride bonds and to the ribose sugar by one phosphate-ester bond.
  • The ATP molecule loses two of its phosphate groups, the beta phosphate and the gamma phosphate, and forms a phosphodiester bond between the 3' carbon of one ribose sugar molecule and the 5' carbon of the next ribose sugar molecule in the Ribonucleic acid polymer.
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