Answer:
the answer would be B proxy server
Big-O notation is a way to describe a function that represents the n amount of times a program/function needs to be executed.
(I'm assuming that := is a typo and you mean just =, by the way)
In your case, you have two loops, nested within each other, and both loop to n (inclusive, meaning, that you loop for when i or j is equal to n), and both loops iterate by 1 each loop.
This means that both loops will therefore execute an n amount of times. Now, if the loops were NOT nested, our big-O would be O(2n), because 2 loops would run an n amount of times.
HOWEVER, since the j-loop is nested within i-loop, the j-loop executes every time the i-loop <span>ITERATES.
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As previously mentioned, for every i-loop, there would be an n amount of executions. So if the i-loop is called an n amount of times by the j loop (which executes n times), the big-O notation would be O(n*n), or O(n^2).
(tl;dr) In basic, it is O(n^2) because the loops are nested, meaning that the i-loop would be called n times, and for each iteration, it would call the j-loop n times, resulting in n*n runs.
A way to verify this is to write and test program the above. I sometimes find it easier to wrap my head around concepts after testing them myself.
Answer:
Download and install a third-party printer application.
Explanation:
Three programs that can print to two printers at the same time are "LeadTools ePrint Professional," "INTELLIscribe" and "Print Distributor." Assign the two printers that you want to use at the same time.
Explanation:
the external form, contours, or outline of someone or something.
Answer:
B. Enable print sharing on the computer.
Explanation:
Enabling print sharing on the computer would be the best choice for providing this functionality with the least effort and cost to the user since it has no networking connectivity.
