Answer:
Explanation:
• The initial dose of the Insulin = 10 Units
The insulin breaks down by about 5% each minute, therefore:
• The decay rate, r= 5%
We want to determine the time it will take for the remaining dosage to be half (5 units) of the original dose.
We use the exponential decay function:
![N(t)=N_o(1-r)^t](https://tex.z-dn.net/?f=N%28t%29%3DN_o%281-r%29%5Et)
Substituting the given values, we have:
![\begin{gathered} 5=10(1-0.05)^t \\ \frac{5}{10}=0.95^t \\ 0.5=0.95^t \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%205%3D10%281-0.05%29%5Et%20%5C%5C%20%5Cfrac%7B5%7D%7B10%7D%3D0.95%5Et%20%5C%5C%200.5%3D0.95%5Et%20%5Cend%7Bgathered%7D)
To solve for t, we change to logarithm form.
Answer:
-10x-28
Step-by-step explanation:
-
Answer:
I believe it's D.
Lmk if I was right, cause I'm 98% sure on this
Answer:
The value of s is "90". A further explanation is given below.
Step-by-step explanation:
The given expression is:
⇒ 10=s÷2+7
i.e,
⇒ ![10=\frac{s}{2+7}](https://tex.z-dn.net/?f=10%3D%5Cfrac%7Bs%7D%7B2%2B7%7D)
On solving the above expression, we get
⇒ ![10=\frac{s}{9}](https://tex.z-dn.net/?f=10%3D%5Cfrac%7Bs%7D%7B9%7D)
On applying cross-multiplication, we get
⇒ ![10\times 9=s](https://tex.z-dn.net/?f=10%5Ctimes%209%3Ds)
⇒ ![90 = s](https://tex.z-dn.net/?f=90%20%3D%20s)