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Sladkaya [172]
2 years ago
10

A restaurant offers delivery for their pizzas. The total cost is a delivery fee added to the price of the pizzas. One customer p

ays $25 to have 2 pizzas delivered. Another customer pays $58 for 5 pizzas. How many pizzas are delivered to a customer who pays $80
Mathematics
1 answer:
FromTheMoon [43]2 years ago
6 0

Answer:

7 pizzas

Step-by-step explanation

First we subtract 58-25=33

Then we subtract 5-2=3

Now, we have 33 over 3 so we divide them and we get 11

So, that means that each pizza costs $11 and the fee that they charge for each pizza is 3.

So if the customer pays $80 that means that he bought 7 pizzas and he payed $3 fee.

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I need help
marysya [2.9K]

Answer: Company C

Step-by-step explanation:

A: $150

B: $160

C: $140

D: $170

So Company C has the best rate.

6 0
3 years ago
Find the smallest positive $n$ such that \begin{align*} n &\equiv 3 \pmod{4}, \\ n &\equiv 2 \pmod{5}, \\ n &\equiv
Alex777 [14]

4, 5, and 7 are mutually coprime, so you can use the Chinese remainder theorem right away.

We construct a number x such that taking it mod 4, 5, and 7 leaves the desired remainders:

x=3\cdot5\cdot7+4\cdot2\cdot7+4\cdot5\cdot6

  • Taken mod 4, the last two terms vanish and we have

x\equiv3\cdot5\cdot7\equiv105\equiv1\pmod4

so we multiply the first term by 3.

  • Taken mod 5, the first and last terms vanish and we have

x\equiv4\cdot2\cdot7\equiv51\equiv1\pmod5

so we multiply the second term by 2.

  • Taken mod 7, the first two terms vanish and we have

x\equiv4\cdot5\cdot6\equiv120\equiv1\pmod7

so we multiply the last term by 7.

Now,

x=3^2\cdot5\cdot7+4\cdot2^2\cdot7+4\cdot5\cdot6^2=1147

By the CRT, the system of congruences has a general solution

n\equiv1147\pmod{4\cdot5\cdot7}\implies\boxed{n\equiv27\pmod{140}}

or all integers 27+140k, k\in\mathbb Z, the least (and positive) of which is 27.

3 0
3 years ago
7.1 + 16.04 – .2 = ? <br><br>       A. 23.34   B. 2.294   C. 23.12   D. 22.94
tamaranim1 [39]
The answer you're looking for my good lad is C
6 0
3 years ago
Read 2 more answers
What are the first five multiples of 7​
sukhopar [10]

Answer:

7, 14, 21, 28, 35

Step-by-step explanation:

brainliest is appreciated

6 0
3 years ago
Read 2 more answers
Ann, Claire, and Josh collect stickers. One week, Ann collects 7 more stickers than Josh. Josh collects twice as many stickers a
UkoKoshka [18]

Answer:

Claire = 30 stickers

Josh = 60 stickers

Ann = 67 stickers

Step-by-step explanation:

Let

Claire stickers= x

Josh = 2x

Ann= 2x + 7

Total stickers = 157

Total stickers = Claire stickers + Josh stickers + Ann stickers

157 = x + (2x) + (2x+7)

157 = x + 2x + 2x + 7

157 = 5x + 7

Subtract 7 from both sides

157 - 7 = 5x + 7 - 7

150 = 5x

Divide both sides by 5

150/5 = x

30 = x

x = 30

Claire stickers= x

=30 stickers

Josh = 2x

= 2(30)

= 60 stickers

Ann= 2x + 7

= 2(30) + 7

= 60 + 7

= 67 stickers

Claire = 30 stickers

Josh = 60 stickers

Ann = 67 stickers

6 0
3 years ago
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