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dybincka [34]
4 years ago
11

PLEASE HELP!!!!!

Mathematics
1 answer:
lianna [129]4 years ago
5 0
Try this option:
A. f(4)=7 - false; explanation: x=4, it means that x>0 and x²-1=4²-1=15 ⇒ f(4)=15.
B. f(1)=0 - true; explanation: x=1, it means that x>0 and x²-1=1-1=0.
C. f(-1)=2 - true; explanation: x=-1, it means that x<0 and -x+1=1+1=2.
D. f(-2)=0 - false; explanation: x=-2, it means that x<0 and -x+1=2+1=3 ⇒ f(-2)=3.
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The lenght of one <br><br> plz answer right show work or describe
Natasha2012 [34]
Since its a right triangle, you can use a² + b² = c²
one of the legs is a and the other leg is b it doesn't matter which one because its addition and works the same way c needs to be the hypotenuse 

so its a² + 48² = 50²
a² + 2304 = 2500
    - 2304    -2304
          a² =  196
      √a² = √196
         a = 14
7 0
3 years ago
Which Statement is true?
const2013 [10]

Answer:

I dont understand it doesnt shoe the question for me

8 0
3 years ago
A physician orders 140mg of a medication to give orally. You have 125mg/5mL on hand. What is the correct dose of medication to g
adelina 88 [10]
<h2>Hello!</h2>

The answer is: The correct dose of medication to give is 5.6 mL

<h2>Why?</h2>

To solve this problem we need to establish a relationship between the prescripted medication and the available solution.

Let's write the needed equations to establish the relantionship:

\frac{125mg}{5mL}=1\\\\125mg=5mL

The available solution means 125 mg each 5 mL of solution, so:

\frac{125mg}{5mL}=\frac{140mg}{x}\\\\x*\frac{125mg}{5mL}=140mg\\\\x=140mg*\frac{5ml}{125mg}=\frac{700mg*mL}{125mg}=5.6mL

Hence, the correct dose of medication to give is 5.6 mL of the 125 mg/5mL solution.

Have a nice day!

3 0
3 years ago
Factor as the product of two binomials <br> X^2 +8x +12 = ?
aksik [14]
The answer to this is (x+6)(x+2)
4 0
3 years ago
I have the answer, 2-(3/x+2)
Marat540 [252]

Start with the answer format we want, and work your way toward forming a single fraction like so

a + \frac{b}{x+2}\\\\a*1+\frac{b}{x+2}\\\\a*\frac{x+2}{x+2}+\frac{b}{x+2}\\\\\frac{a(x+2)}{x+2}+\frac{b}{x+2}\\\\\frac{a(x+2)+b}{x+2}\\\\\frac{ax+2a+b}{x+2}\\\\\frac{ax+(2a+b)}{x+2}\\\\

Compare that last expression to (2x+1)/(x+2). Notice how the ax and 2x match up, so a = 2 must be the case.

Then we have 2a+b as the remaining portion in the numerator. Plugging in a = 2 leads to 2a+b = 2*2+b = 4+b. Set this equal to the +1 found in (2x+1)/(x+2) to have the terms match.

So, 4+b = 1 leads to b = -3

Therefore, a = 2 and b = -3

------------------------------------------------

An alternative route:

\frac{2x+1}{x+2}\\\\\frac{2x+1+0}{x+2}\\\\\frac{2x+1+4-4}{x+2}\\\\\frac{(2x+4)+1-4}{x+2}\\\\\frac{2(x+2)-3}{x+2}\\\\\frac{2(x+2)}{x+2}+\frac{-3}{x+2}\\\\2-\frac{3}{x+2}\\\\

I added and subtracted 4 in the third step so that I could form 2x+4, which then factors to 2(x+2). That way I could cancel out a pair of (x+2) terms toward the very end.

------------------------------------------------

Other alternative methods involve synthetic division or polynomial long division. They are slightly separate but related concepts.

3 0
3 years ago
Read 2 more answers
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