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Dovator [93]
4 years ago
14

Solve for x if 5=log3 (x^2+18)

Mathematics
1 answer:
nignag [31]4 years ago
6 0
Try to rewrite the equation; 

You know that 5 can be written as log3(3^5)

log3(3^5)=log3(x^2+18) <-- you can now cancel out log3
3^5=x^2+18 
243-18=x^2 
225=x^2 
√225=x
+-15=x 

You see that even if x is negative, the squared will always give a positive answer. Therefore, +15 and -15 are both possible answers. 

Hope I helped :)  
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Parabola Equations - Algebra
mash [69]

Answer:

h=-\frac{1}{6}x^2+2x

Step-by-step explanation:

The height of the tunnel is modeled by:

h=rx^2+tx

Where r and t are constants.

We know that the maximum height of the tunnel h is 6 meters.

And at ground level, the width is 12 meters.

And we want to determine the equation of the parabola.

First, since this is a quadratic, our maximum height h will occur at the vertex of our equation.

The vertex is given by:

(-\frac{b}{2a}, f(-\frac{b}{2a}))

In our case, we have the function:

h=(r)x^2+(t)x

Hence, a=r; b=t; and c=0.

Therefore, our vertex is:

\Rightarrow -\frac{t}{2r}

Thus, if we substitute this back into our equation, we should get 6 since 6 is the maximum height which is determine by the vertex. In other words:

(6)=r(-\frac{t}{2r})^2+t(-\frac{t}{2r})

Simplify:

6=r(\frac{t^2}{4r^2})-\frac{t^2}{2r}

Simplify:

6=\frac{t^2}{4r}-\frac{t^2}{2r}

Combine fractions:

6=\frac{t^2}{4r}-\frac{2t^2}{4r}=\frac{-t^2}{4r}

Multiply both sides by the denominator:

24r=-t^2

Let's solve for the constant r. Divide both sides by 24. Hence:

r=-\frac{t^2}{24}

Now, we can use our knowledge of the width.

We know that the width is 12 meters at ground level.

Hence, when h=0, the <em>difference of our roots</em> is 12.

So:

0=rx^2+tx

We can factor:

0=x(rx+t)

By the Zero Product Property:

x=0\text{ or } rx+t=0

So, the first zero is 0.

Therefore, the second zero <em>must be 12</em> to ensure that our width is 12.

Let's isolate the second zero. Subtract t from both sides:

rx=-t

Divide both sides by r:

x=-\frac{t}{r}

We know that this zero must be 12. Thus:

12=-\frac{t}{r}

We have previously solved for r. Substitute:

12=-\frac{t}{\frac{-t^2}{24}}

Simplify:

12=\frac{24}{t}

Take the reciprocal of both sides:

\frac{t}{24}=\frac{1}{12}

Multiply both sides by 24. Hence, the value of t is:

t=2

Now, we can find r. r is given by:

r=-\frac{t^2}{24}

By substituting 2 for t, then, we acquire that:

r=-\frac{(2)^2}{24}=-\frac{4}{24}=-\frac{1}{6}

Therefore, for:

h=rx^2+tx

Our equation is:

h=-\frac{1}{6}x^2+2x

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3 years ago
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makvit [3.9K]

Answer:3.694x10^2

Step-by-step explanation:

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4 years ago
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VladimirAG [237]
No 27/107 is not irrational because both numbers can be simplified to be a smaller fraction/number.
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What is the square root of 16x36?
uysha [10]
The square root is 4x6

If you have anymore, this should help you: http://www.math.com/students/calculators/source/square-root.htm
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4 years ago
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What’s the answer???(SOMEONE PLEASE HELP ME)
Zina [86]

Basically you can't divide by 0 so -3 and 5 are not in the domain

Answer is the first option

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3 years ago
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