We presume your cost function is
c(p) = 124p/((10 +p)(100 -p))
This can be rewritten as
c(p) = (124/11)*(10/(100 -p) -1/(10 +p))
The average value of this function over the interval [50, 55] is given by the integral

This evaluates to
(-124/55)*(ln(65/60)+10ln(45/50)) ≈ 2.19494
The average cost of removal of 50-55% of pollutants is about
$2.19 hundred thousand = $219,000
A.9×6x - ( 9×2)=
64x-18 = 0
64x=18
x=18/64 =1/3 =0.3
B. 64x+18=0
64x= -18
x =-18/64
x= -1/3
x = -0.3
Answer:
you need to sell 60 cups
Step-by-step explanation:
48÷0.80= 60 cups
hope it helps!
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