You can take the log of the left and right hand side, and then apply the <span>logarithm rules:
log(a</span>ˣ) = x·log(a)
log(ab) = log(a) + log(b)
log(9^(x-1) * 2^(2x+2)) = log(6^(3x))
log(9^(x-1)) + log(2^(2x+2)) = 3x log(6)
(x-1) log(9) + (2x+2) log(2) - 3x log(6) = 0
x(log9 + 2log2 - 3log6) = log9 - 2log2
x = (log9 - 2log2) / (log9 + 2log2 - 3log6)
simplifying by writing log9 = 2log3 and log6 = log2+log3
x= 2(log3 - log2) / (2log3 + 2log2 - 3log2 - 3log3) =
x= -2(log3 - log2) / (log3 + log2) = -2 log(3/2) / log(6)
So 6^x = 4/9
Simply add the three decimals to find Kareem's total distance.
1.6 + 11.5 + 15 = 28.1
(0.6 + 0.5 = 1.1, 1 + 11 + 15 = 27, 27 + 1.1 = 28.1)
<h2>Answer:</h2>
<u>Kareem ran </u><u>28.1 km</u><u> on those three days.</u>
I hope this helps :)
<span>-12 = pico(p)
So 10^-12 L = 1 pL
Use following to find the count of 10^-12 L are there in 2.3×10^-10 L
2.3×10^-10 / (10^-12) = 2.3×10^2 = 230 pL
-6 = micro (µ)
4.7×10^-6 g = 4.7 µg
1.85×10^-12 m = 1.85 pm
6 = Mega (M)
16.7×10^6 s = 16.7 Ms
So the answer is 16.7 Ms</span>
