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3 years ago

Kendra placed the numbers -3/8, 0.27, -0.3 and 4/7 on the number line. Which of the numbers is furthest from zero

1 answer:

8 0

In order to solve this, you're going to need something called "absolute value" (it's basically putting vertical lines around a term like |x| ). And you're going to use it for all the values you have, and find the largest number. This is simply because absolute value literally means the distance from zero. So, doing the problem for you: you'd start off by finding the absolute value for each of those values [3/8 ,0.27, 0.3, 4/7]. It is only a matter of finding out that 4/7 is the largest of those four numbers. Hope I helped :)

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Pls help me bestie with this question ASAP thank you

melomori [17]

Answer:

Its B 0.454554555

Step-by-step explanation:

it has a pattern which is repeating. So its known as rational number..

7 0

3 years ago

Simplify each sum or difference. State any restrictions on the variables.

Dvinal [7]

Answer:

2(d-2)/(2d+1) or 1 - 5/(2d+1)

d can not be -½

Step-by-step explanation:

(d-3)/(2d+1) + (d-1)/(2d+1)

Lcm: 2d+1

(d-3+d-1)/(2d+1)

= (2d-4)/(2d+1)

= 2(d-2)/(2d+1)

If further simplification required:

= (2d-4)/(2d+1)

= (2d+1-5)/(2d+1)

= (2d+1)/(2d+1) - 5/(2d+1)

= 1 - 5/(2d+1)

2d+1 = 0

When d = -½

So d can not be -½ because when the denominator becomes 0, fraction becomes undefined

7 0

3 years ago

Angle (theta) is in standard position. If (8,-15) is on the terminal ray of angle (theta), find the values of the trigonometric

mariarad [96]

Answer:

$\sin \theta =\frac{-15}{17}\\cos \theta =\frac{8}{17}\\\tan \theta =\frac{-15}{8}\\\csc \theta =\frac{-17}{15}\\\sec \theta =\frac{17}{8}\\\cot \theta =\frac{-8}{15}$

Step-by-step explanation:

Given: (8,-15) is on the terminal ray of angle

To find: All the trigonometric ratios

Solution:

Trigonometry is a branch of mathematics that explain relationship between the sides and angles of triangles.

If (x, y) lies on the terminal side of θ then $r=\sqrt{x^2+y^2}$

$r=\sqrt{(8)^2+(-15)^2}=\sqrt{64+225}=\sqrt{289}=17$ units

$\sin \theta =\frac{y}{r}=\frac{-15}{17}\\cos \theta =\frac{x}{r}=\frac{8}{17}\\\tan \theta =\frac{y}{x}=\frac{-15}{8}\\\csc \theta =\frac{1}{\sin \theta }=\frac{-17}{15}\\\sec \theta =\frac{1}{cos \theta}=\frac{17}{8}\\\cot \theta =\frac{1}{\tan \theta}=\frac{-8}{15}$

6 0

3 years ago

Sherry had an ending balance f 125.36, outstanding deposits of 153.53, and utstanding checks of $100.19. What was her checkbook

DENIUS [597]

Answer:

The checkbook balance is $178 .7.

Step-by-step explanation:

As given

Sherry had an ending balance $ 125.36, outstanding deposits of $153.53, and outstanding checks of $100.19.

Thus

Checkbook balance = Ending balance + Outstanding deposits - Outstanding checks

Putting the values in the above

Checkbook balance = $ 125.36 + $153.53 - $100.19

= $ 278.89 - $100.19

= $ 178.7

Therefore the checkbook balance is $178 .7.

6 0

3 years ago

I need the answer fast

denis23 [38]

Answer:

Step-by-step explanation:

5 0

3 years ago

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