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3 years ago

A business owes $8000 on a loan. Every month, the business pays 1/2 of the amount remaining on the loan.

1 answer:

3 0

Here is the answer to the given problem above. Given that the business owes $8000 on a loan and every month, it pays 1212. So for the first month, the remaining is 6,788. On the second month is 5,576, and on the third month, it is 4,364. In the fourth month, the remaining would be 3,152, and in the fifth month is 1,940. Therefore, on the sixth month, if the business pays 1,212 still, the remaining would be $728 only. Hope this answer helps.

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5. The parts that are added or subtracted in an algebraic<br> expression are called?

vichka [17]

Answer:

They are known as terms in algebraic expression

Step-by-step explanation:

3 0

3 years ago

Find the solution of the following system of equations -5+2y=9 3x+5y=7

Rudiy27

Answer:

$x=-\frac{28}{3}\\\\y=7$

Step-by-step explanation:

Given the system of equations:

$\left \{ {{-5+2y=9} \atop {3x+5y=7}} \right.$

You can pply Substitution method:

First you must solve for "y" from the first equation:

$-5+2y=9\\\\2y=9+5\\\\2y=14\\\\y=\frac{14}{2}\\\\y=7$

Therefore, the second and final step to solve the system of equations is to substitute the value of "y" into the second equation and solve for "x":

$3x+5(7)=7\\3x=7-35\\\\x=-\frac{28}{3}$

5 0

3 years ago

Multiply 3/sqrt17- sqrt2 by which fraction will produce an equivalent fraction with rational denominator

zzz [600]

Answer:

Step-by-step explanation:

To simplify something that looks like $\frac{\text{whatever}}{\sqrt{a}-\sqrt{b}}$ you would multiply the top and bottom by the conjugate of the bottom. So you multiply the top and bottom for this problem I just made by:

$\sqrt{a}+\sqrt{b}$ .

If you had $\frac{\text{whatever}}{\sqrt{a}+\sqrt{b}}$ , then you would multiply top and bottom the conjugate of $\sqrt{a}+\sqrt{b}$ which is $\sqrt{a}-\sqrt{b}$ .

The conjugate of a+b is a-b.

These have a term for it because when you multiply them something special happens. The middle terms cancel so you only have to really multiply the first terms and the last terms.

Let's see:

(a+b)(a-b)

I'm going to use foil:

First: a(a)=a^2

Outer: a(-b)=-ab

Inner: b(a)=ab

Last: b(-b)=-b^2

--------------------------Adding.

a^2-b^2

See -ab+ab canceled so all you had to do was the "first" and "last" of foil.

This would get rid of square roots if a and b had them because they are being squared.

Anyways the conjugate of $\sqrt{17}-\sqrt{2}$ is