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3 years ago

Consider the function f(x) = x^{2/3} on the interval [-1,8].

1 answer:

5 0

The right option is (c). The Mean Value Theorem does not apply since f(x) is not differentiable on (-1,8). Because the derivative of f is 2/3 x^(-1/3) which is undefined at x=0.So, that would imply that it is not differentiable along the interval.

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<h3>Answer :</h3>

$\bf (x+y)^2(x-y)^2$

==============

<h3>Solving Steps:</h3>

===============

$\rightarrow \sf x^4-2x^2y^2+y^4$

<u>breakdown</u>

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2 years ago

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Answer:

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