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rusak2 [61]
2 years ago
11

A:36 B:39 C:54 D:108

Mathematics
1 answer:
nordsb [41]2 years ago
3 0
The answer is 36 my friend too the test and I helped him
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Write in point-slope form the equation of the line that is parallel to the given line and passes through the given point.Your fi
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Answer:

y = x

Step-by-step explanation:

The given equation is

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Since all parallel lines have the same slope, the slope of our line is also m=1.

We now use the point-slope formula

y-y_1=m(x-x_1)

Since the line passes through (-1,-1)

We gave

x_1=-1,y_1=-1

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y -  - 1 = 1(x -  - 1)

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Ray CE is the angle bisector of ACD. Which statement about the figure must be true?
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we know that

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\bf =ae^{kt}\qquad &#10;\begin{cases}&#10;1994\impliedby \textit{year 0, starting point}\\&#10;t=0\qquad P=182&#10;\end{cases}\implies 182=ae^{k0}&#10;\\\\\\&#10;182=a\cdot e^0\implies 182=a\cdot 1\implies 182=a&#10;\\\\\\&#10;thus\qquad P=182e^{kt}\\\\&#10;-------------------------------\\\\

\bf P=182e^{kt}\qquad &#10;\begin{cases}&#10;2002\impliedby \textit{8 years later}\\&#10;t=8\qquad P=186&#10;\end{cases}\implies 186=182e^{k8}&#10;\\\\\\&#10;\cfrac{186}{182}=e^{8k}\implies ln\left( \frac{93}{91} \right)=ln(e^{8k})\implies ln\left( \frac{93}{91} \right)=8k&#10;\\\\\\&#10;\cfrac{ln\left( \frac{93}{91} \right)}{8}=k\implies 0.0027\approx k\implies \boxed{P=182e^{0.0027t}}

what's the population in 2004?  well,  from 1994 to 2004 is 10 years later, so t = 10

plug that in, to get P for 2004
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