It can be deduced that the price of the trick cameras will be $5 and the price of the snakes will be $6.25.
Based on the information given, the equation to solve the question will be:
3x + 4y = 40 ...... i
7x + 8y = 85 ...... ii
Multiply equation i by 7
Multiply equation ii by 3
21x + 28y = 280
21x + 24y = 255
Subtract the equations
4y = 25
y = 25/4 = 6.25
Since 3x + 4y = 40
3x + 4(6.25) = 40
3x + 25 = 40
3x = 40 - 25.
3x = 15
x = 15/3 = 5
Therefore, the price of the trick cameras will be $5 and the price of the snakes will be $6.25.
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The Olympics Games that follow the 28th games will be "XXIX Games."
The Olympic Games that follow the 28th Olympic games is the 29th Olympic Games.
29 in Roman numerals is:
= XXVIII
An X in Roman numerals is 10 so the first two Xs are to signify "20."
An "IX" in Roman numerals is "9" which will then take the number to 29.
It will therefore be the "XXIX Olympic Games."
In conclusion, the number 29 is XXIX in Roman numerals so Olympic Games after the 28th games will be "XXIX Games."
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A full rotation is 360 degrees so the required angle is 360/12 = 30 degrees.
I assume you're asked to solve
4 cos²(<em>x</em>) - 7 cos(<em>x</em>) + 3 = 0
Factor the left side:
(4 cos(<em>x</em>) - 3) (cos(<em>x</em>) - 1) = 0
Then either
4 cos(<em>x</em>) - 3 = 0 <u>or</u> cos(<em>x</em>) - 1 = 0
cos(<em>x</em>) = 3/4 <u>or</u> cos(<em>x</em>) = 1
From the first case, we get
<em>x</em> = cos⁻¹(3/4) + 2<em>nπ</em> <u>or</u> <em>x</em> = -cos⁻¹(3/4) + 2<em>nπ</em>
and from the second,
<em>x</em> = <em>nπ</em>
where <em>n</em> is any integer.