Midpoint is a the mid point of the two points. while distance the length from b/w them.
<span>The length is:
the square root of [ (the difference in 'x' values)² + (the difference in 'y' values)² ]
D = √ [ (-2-6)² + (5-2)² ]
= √ [ (-8)² + (3)² ]
= √ (64 + 9) = √75 = 5√3 = <u>8.66</u> (rounded to 3 sig-figs)</span>
15.8 as the square root of (13^2+9^2) is less then the square root of (10^2+14^2) you can do this by using the Pythagorean Theorem.
Answer:
16.93 m
Step-by-step explanation:
The triangle for the given scenario is shown below.
From the triangles
and
,
AB is the pole height, BC or BD is the distance of either of the wire guys from the foot of pole, and
or
is the angle that each either of the guys make with the top of pole.
Let the distance of either of the wire guys from the foot of pole be
.
Now, consider
.
Given: AB = 9 m, BC =
, and
°.
Using tan ratio of the angle C, we get

Therefore, 16.93 m away from the foot of the pole are the guys anchored.
F(x) = xe⁻ˣ
f(x)' = x* -e⁻ˣ + e⁻ˣ
f(x)' = 0 => x = 1
f(1) = 1/e = 0.368