Answer:
the initial height of the cannon ball
Step-by-step explanation:
- Time (t) is basically how many seconds or minutes you factor into the given function. 16(time in exact seconds or minutes)^2+40(time in exact seconds or minutes) +5
- The +5 can only be where the cannonball was initially fired from logically. The Velocity formula is already there for you to plug the time into^^^
(I used time in minutes/seconds to try and explain what the function is asking)
Answer:
3.5588 x 10⁸
Step-by-step explanation:
(3.1 x 10³) (1.148 x 10⁵) = (3.1 x 1.148) (10³ x 10⁵)
= 3.5588 x 10⁸
Use the Law of Sines (sina/A=sinb/B=sinc/C for any triangle)
YZ/sin30=50/sin90
YZ=50sin30 (sin90=1 :P)
YZ=25m
Use the 30,60,90° triangle ratios 1, √3, 2
YZ/1=50/2
YZ=25m
Using the Pythagorean Theorem....
(2*25)^2=YZ^2+(√3*YZ)^2
2500=YZ^2+3YZ^2
2500=4YZ^2
625=YZ^2
25m=YZ
Answer:
The function given is non-linear.
Step-by-step explanation:
The slope between (0, 2) and (2,6):
![\frac{6-2}{2-0}=\frac{4}{2}=\boxed{2}](https://tex.z-dn.net/?f=%5Cfrac%7B6-2%7D%7B2-0%7D%3D%5Cfrac%7B4%7D%7B2%7D%3D%5Cboxed%7B2%7D)
The slope between (2,6), and (3, 12):
![\frac{12-6}{3-2}=\frac{6}{1}=\boxed{6}](https://tex.z-dn.net/?f=%5Cfrac%7B12-6%7D%7B3-2%7D%3D%5Cfrac%7B6%7D%7B1%7D%3D%5Cboxed%7B6%7D)
Since the slopes are not equal to each other, the function is non-linear. A linear function's slope must stay consistent.
Hope this helps.