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2 years ago

I’m lazy to do dis please halp me

Mathematics

1 answer:

Olenka [21]2 years ago

6 0

There could be 6 groups of 7 kids, 7 groups of 6 kids, or 14 groups of 4 kids.
56÷7=6 or 56÷4=14.

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Write the ratio using fraction notation and reduce.

valkas [14]

The ratio using fraction notation of $5 to $35 would be 7.

<h3>What is a fraction?</h3>

A fraction represents a part of a number or any number of equal parts.

To convert a ratio into a fraction,

We will simply use the first number as the numerator and the second number as the denominator.

So the fraction = 35/5.

= 7

Since there are no more common factors, the fraction is in its lowest form which is 7.

Learn more about fractions;

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3 0

1 year ago

Can some help me pls

Rama09 [41]

please give your full name

5 0

2 years ago

Which is the value of this expression when p = - 2 and q = -1?

Elan Coil [88]

Answer: -4 is the answer

Step-by-step explanation:

4 0

2 years ago

If f(x)=5fx3-2 and g(x)=x+1, find (f-g)(x)

kirza4 [7]

Answer:

5x^3-x-3

Step-by-step explanation:

5x^3-2-x-1

5x^3-x-3

3 0

2 years ago

A total of 1 232 students have taken a course in Spanish, 879 have taken a course in French, and 114 have taken a course in Russ

ElenaW [278]

Answer:

$n(S\cap F \cap R)=7$

Step-by-step explanation:

The Universal Set, n(U)=2092

$n(S)=1232\\n(F)=879\\n(R)=114$

$n(S\cap R)=23\\n(S\cap F)=103\\n(F\cap R)=14$

Let the number who take all three subjects, $n(S\cap F \cap R)=x$

Note that in the Venn Diagram, we have subtracted $n(S\cap F \cap R)=x$ from each of the intersection of two sets.

The next step is to determine the number of students who study only each of the courses.

$n(S\:only)=1232-[103-x+x+23-x]=1106+x\\n(F\: only)=879-[103-x+x+14-x]=762+x\\n(R\:only)=114-[23-x+x+14-x]=77+x$

These values are substituted in the second Venn diagram

Adding up all the values

2092=[1106+x]+[103-x]+x+[23-x]+[762+x]+[14-x]+[77+x]

2092=2085+x

x=2092-2085

x=7

The number of students who have taken courses in all three subjects, $n(S\cap F \cap R)=7$

3 0

2 years ago