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Tasya [4]
3 years ago
13

I guess u have to find the area

Mathematics
2 answers:
Nesterboy [21]3 years ago
7 0
18
Because 6•3= 18
Hope this helped
attashe74 [19]3 years ago
7 0
6ft x 3ft = 18ft cause it say l•w
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How do you do a expression
8090 [49]
1. get rid of your parenthesis 
2. in order to do so you must look inside of the parenthesis and check if you have any like terms if so combine them
3. next use the distribution property or otherwise known as the rainbow
4. if you have an exponent to the right of your parenthesis then use the exponent rule
5. combine like terms by adding coefficients
6. finally combine the constants





5 0
3 years ago
Needed ASAP! Please help!
Strike441 [17]

Answer:

the answer is B

Step-by-step explanation: i added the two fractions

8 0
3 years ago
Determine whether the solution of -2x = -15 is<br> Greater than or less than -15
brilliants [131]

Positive numbers are always greater than -15. Therefore, it's a greater than.

-2x = - 15

Dividing both sides by -2, we get

x = 7.5

Negative cancels on both sides, so we get a positive equation.

Positive numbers are always greater than -15. Therefore, it's a greater than.

What is greater than or less than?

  • Greater than and less than are the comparison symbols.
  • When the number is bigger or smaller than the other, then greater than and less than symbols are used.
  • If the number is greater than the other, the greater than (>) symbol is used.
  • If the number is lesser than the other, the less than the (<) symbol is used.

To learn more about greater than and less than, visit: brainly.com/question/15746367

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5 0
1 year ago
Simplify 3x^2y^3•x^4y
kirill115 [55]

Answer:

Step-by-step explanation:

3x²y³·x⁴y = 3x²x⁴y³y = 3x²⁺⁴y³⁺¹ = 3x⁶y⁴

7 0
3 years ago
Find the Taylor series for f(x) centered at the given value of a. [Assume that f has a power series expansion. Do not show that
kherson [118]

Answer:

The answer is

f(x) = {\displaystyle  8 + \frac{-28}{1}(x+2)+\frac{-36}{2!}(x+2)^2 + \frac{-18}{3!}(x+2)^2 }

Step-by-step explanation:

Remember that Taylor says that

f(x) = {\displaystyle \sum\limits_{k=0}^{\infty} \frac{f^{(k)}(a) }{k!}(x-a)^k }

For this case

f^{(0)} (-2) = 8(-2)-3(-2)^3 = 8\\f^{(1)} (-2) = 8-3(3)(-2)^2 = -28\\f^{(2)} (-2) = -3(3)2(-2) = -36\\f^{(2)} (-2) = -3(3)2 = -18

f(x) = {\displaystyle  8 + \frac{-28}{1}(x+2)+\frac{-36}{2!}(x+2)^2 + \frac{-18}{3!}(x+2)^2 }

5 0
3 years ago
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