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2 years ago

Find each missing measure.

1 answer:

6 0

The answer

a = 84

ac = 9

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frez [133]

The answers are b and c

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3 years ago

andrew-mc [135]

40 i belive but im not sure

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3 years ago

Andrew [12]

The only way to do this is when there is a decimal.

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3 years ago

djyliett [7]

Answer:

answer is 1

Step-by-step explanation:

just did test on edge

4 0

3 years ago

ira [324]

$\dfrac{\frac{x+2}{x^2+2x-3}}{\frac{x+2}{x^2-x}}$

If $x\neq-2$ , then we can immediately cancel the factors of $x+2$ :

$\dfrac{\frac1{x^2+2x-3}}{\frac1{x^2-x}}=\dfrac{x^2-x}{x^2+2x-3}$

Factorize the numerator and denominator:

$x^2-x=x(x-1)$

$x^2+2x-3=(x+3)(x-1)$

Next, if $x\neq1$ , then

$\dfrac{x^2-x}{x^2+2x-3}=\dfrac{x(x-1)}{(x+3)(x-1)}=\dfrac x{x+3}$

8 0

3 years ago