3 years ago

How do I find the value of x?

Mathematics

1 answer:

svetoff [14.1K]3 years ago

4 0

Answer:

x = 2

Step-by-step explanation:

If ΔABC~ΔAED then:

$\dfrac{AC}{AD}=\dfrac{BC}{ED}\\\\\\\dfrac{x+4}{4}=\dfrac{3}{2}\\\\\dfrac{x+4}{4}=\dfrac64\\\\x+4=6\\\\x=2$

You might be interested in

What is the measure of angle a?

kykrilka [37]

Answer:

a = 63˚

Step-by-step explanation:

1. Recognize that any triangle = ∑180˚

2. 180-81-b-a=0

3. 180-117=63˚

6 0

3 years ago

5x^3+9x^2+6x+1 times the polynomial x?

zhannawk [14.2K]

Answer:

$(5x^{4} + 9x^{3} + 6x^{2} + 1x)$

Step-by-step explanation:

$(5x^{3} + 9x^{2} + 6x + 1) * x$

Multiplying the term by x, adds 1 to the power.

$5x^{3} * x = 5x^{3+1} = 5x^{4}$

Therefore

$(5x^{3} + 9x^{2} + 6x + 1) * =\\(5x^{4} + 9x^{3} + 6x^{2} + 1x)$

6 0

4 years ago

Three times the difference of ten and a number is four.

Paul [167]

Answer:

3 (10-a) = 4 i think

Step-by-step explanation:

7 0

3 years ago

In △ABC, m∠A=27°, c=14, and m∠B=25°. Find a to the nearest tenth.

Alenkinab [10]

Answer:

8.1

Step-by-step explanation:

3 0

3 years ago

Triangle XYZ is located at X (−2, 1), Y (−4, −3), and Z (0, −2). The triangle is then transformed using the rule (x−1, y+3) to f

Airida [17]

<span>You have to apply the rule to the XYZ coordinates, so X'= (-2-1, 1+3) Y'= (-4-1, -3+3) Z'= (0-1, -2+3) So the new coordinates are X' (-3, 4), Y' (-5, 0), and Z'(-1, 1) This is actually translation not transformation, as the shape doesn't change it just moves</span>

6 0

3 years ago