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ale4655 [162]
2 years ago
14

How do I find the value of x?

Mathematics
1 answer:
svetoff [14.1K]2 years ago
4 0

Answer:

             x = 2

Step-by-step explanation:

If ΔABC~ΔAED then:

                                 \dfrac{AC}{AD}=\dfrac{BC}{ED}\\\\\\\dfrac{x+4}{4}=\dfrac{3}{2}\\\\\dfrac{x+4}{4}=\dfrac64\\\\x+4=6\\\\x=2

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Patricia compró 10 estampillas de correos unas de $3.00 y otras de $1.00. Si pago con $18.00 en total. ¿Cuántas pago por cada un
Ganezh [65]

Answer:

Entonces Patricia necesitara 4 estampas de $3 dolares y 6 estampas de $1 dolar

Step-by-step explanation:

Cuatro estampas de tres dolares cada una es:

3 × 4 = 12

Ahora necesitamos encontrar  cuantas estampas mas Patricia puede comprar. Podemos hacer esto restando 12 a 18, que es el costo total de las estampas menos del valor encontrado

18 - 12 = 6

Ahora sabemos que Patricia necesita 6 dolares de estampas ($1 estampas) para acompletar las 10 estampas  dando un total de $18 dolares.

6 × 1 = 6 < sumar 6 de 12

12 + 6 = 18

Entonces Patricia necesitara 4 estampas de $3 dolares y 6 estampas de $1 dolar

6 0
3 years ago
ΔABC has vertices A(2,4), B(6,0), AND C(-4,0).
arlik [135]
<span>ΔABC is not a right triangle.</span>
3 0
3 years ago
Read 2 more answers
BRAINLIEST !! Evaluate the following fractions giving your awnser in its simplest form.
Pie

Answer:

question no c 0•08

Step-by-step explanation:

at first

1/4+1/3-1/2

0•25+0.33-0.50

0.58-0.50

0.08 answer

7 0
1 year ago
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100 Brainliest up for grabs to person who can answer all of these with no links:
kogti [31]

Using a discrete probability distribution, it is found that:

a) There is a 0.3 = 30% probability that he will mow exactly 2 lawns on a randomly selected day.

b) There is a 0.8 = 80% probability that he will mow at least 1 lawn on a randomly selected day.

c) The expected value is of 1.3 lawns mowed on a randomly selected day.

<h3>What is the discrete probability distribution?</h3>

Researching the problem on the internet, it is found that the distribution for the number of lawns mowed on a randomly selected dayis given by:

  • P(X = 0) = 0.2.
  • P(X = 1) = 0.4.
  • P(X = 2) = 0.3.
  • P(X = 3) = 0.1.

Item a:

P(X = 2) = 0.3, hence, there is a 0.3 = 30% probability that he will mow exactly 2 lawns on a randomly selected day.

Item b:

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.2 = 0.8

There is a 0.8 = 80% probability that he will mow at least 1 lawn on a randomly selected day.

Item c:

The expected value of a discrete distribution is given by the <u>sum of each value multiplied by it's respective probability</u>, hence:

E(X) = 0(0.2) + 1(0.4) + 2(0.3) + 3(0.1) = 1.3.

The expected value is of 1.3 lawns mowed on a randomly selected day.

More can be learned about discrete probability distributions at brainly.com/question/24855677

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2 years ago
What's the difference between 4.5 and -3.5​
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Answer:

4.5 and -3.5 are different numbers for one then on is positive and one is negative

Step-by-step explanation:

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3 years ago
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