Answer:
![y=1.383x-1.526](https://tex.z-dn.net/?f=y%3D1.383x-1.526)
Step-by-step explanation:
The given data table is
x : 4 7 10 12 13
y : 5 7 12 14 18
We need to find the equation of the best fit line.
The general form of a best fit line is
.... (1)
where, m is slope and b is y-intercept.
![m=\frac{\sum_{i=1}^nx_iy_i-n\overline{x}\overline{y}}{\sum_{i=1}^nx_i^2-n\overline{x}^2}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7B%5Csum_%7Bi%3D1%7D%5Enx_iy_i-n%5Coverline%7Bx%7D%5Coverline%7By%7D%7D%7B%5Csum_%7Bi%3D1%7D%5Enx_i%5E2-n%5Coverline%7Bx%7D%5E2%7D)
![b=\overline{y}-b\overline{x}](https://tex.z-dn.net/?f=b%3D%5Coverline%7By%7D-b%5Coverline%7Bx%7D)
Using the graphing calculator we get
![m=1.38321\approx 1.383](https://tex.z-dn.net/?f=m%3D1.38321%5Capprox%201.383)
![b=-1.52555\approx -1.526](https://tex.z-dn.net/?f=b%3D-1.52555%5Capprox%20-1.526)
Substitute m=1.383 and b=-1.526 in equation (1).
![y=1.383x-1.526](https://tex.z-dn.net/?f=y%3D1.383x-1.526)
Therefore, the equation of best fit line is
.
Answer:
Step-by-step explanation:
<u>Use the interest formula:</u>
- I = Prt, where P - amount of loan, r- interest rate, t- time in years
<u>Robert:</u>
- I = 30000*(4.9/100)*4 = 5880
<u>Susan:</u>
- I = 30000*(4.5/100)*6 = 8100
<u>Difference in amounts of interest:</u>
Susan paid $2220 more
Nothing times 6 equals 64 because 6 times 10 is 60 and 6 times 11 is 66 so nothing times 6 equals 64
53,380 was the average last year .
<u>Step-by-step explanation:</u>
Here we have , So far this year, the average monthly revenue at Lexington Times is 50,711. That is 5% less than the monthly average was last year. We need to find that What was the average last year . Let's find out:
Let the monthly average was last year be x , According to question the average monthly revenue at Lexington Times is 50,711 but , That is 5% less than the monthly average was last year . Following equation for above scenario is :
⇒ ![x-\frac{5(x)}{100}=50711](https://tex.z-dn.net/?f=x-%5Cfrac%7B5%28x%29%7D%7B100%7D%3D50711)
⇒ ![\frac{100x-5x}{100}=50711](https://tex.z-dn.net/?f=%5Cfrac%7B100x-5x%7D%7B100%7D%3D50711)
⇒ ![\frac{95x}{100}=50711](https://tex.z-dn.net/?f=%5Cfrac%7B95x%7D%7B100%7D%3D50711)
⇒ ![\frac{95x(100)}{100(95)}=\frac{50711(100)}{95}](https://tex.z-dn.net/?f=%5Cfrac%7B95x%28100%29%7D%7B100%2895%29%7D%3D%5Cfrac%7B50711%28100%29%7D%7B95%7D)
⇒ ![x=\frac{50711(100)}{95}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B50711%28100%29%7D%7B95%7D)
⇒ ![x=53380](https://tex.z-dn.net/?f=x%3D53380)
Therefore , 53,380 was the average last year .