Answer:1.69*10^12 J
Step-by-step explanation:
From figure above, using triangle ratio
485/755.5=y/l. Cross multiplying 485l=755.5y Divide via 485) hence l= 755.5y/485
Consider a slice volume Vslice= (755.5y/485)^2∆y; recall density =150lb/ft^3
Force slice = 150*755.5^2.y^2.∆y/485^2
From figure 2 in the attachment work done for elementary sclice
Wslice= 150.755.5^2.y^2.∆y.(485-y)/485^2
= (150*755.5^2*y^2)(485-y)∆y/485
To calculate the total work we integrate from y=0 to y= 485
Ie W=[ integral of 150*755.5^2 *y^2(485-y)dy/485] at y=0 and y= 485
Integrating the above
W= 150*755.5^2/485[485*y^3/3-y^4/4] at y= 0 and y=485
W= 150*755.5^2/485(485*485^3/3-484^4/4)-(485.0^3/3-0^4/4)
Work done 1.69*10^12joules
The expected value of the winnings from the game is $4
<h3>How to determine the expected value?</h3>
The payout probability distribution is given as:
Payout ($) 2 4 6 8 10
Probability 0.5 0.2 0.15 0.1 0.05
The expected value is then calculated as:

This gives
E(x) = 2 * 0.5 + 4 * 0.2 + 6 * 0.15 + 8 * 0.1 + 10 * 0.05
Evaluate the expression
E(x) = 4
Hence, the expected value of the winnings from the game is $4
Read more about expected values at:
brainly.com/question/15858152
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Answer:
you answer is B
Step-by-step explanation:
I am almost 100% sure it is B but correct me if im wrong