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antoniya [11.8K]
3 years ago
8

13 points! Multiply each and write in standard form. 1-8 you do not have to give explanation but it would help. Brainiest to fir

st answerer.

Mathematics
1 answer:
dalvyx [7]3 years ago
5 0

1.

(y - 2)(y - 4)

Multiply all terms on the right with y, then do the same with -2

Multiply y by y:

y^2

Then y by -4:

y^2-4y

Then -2 by y:

y^2-4y-2y

Then -2 by -4:

y^2-4y-2y+8 = y^2-6y + 8\\

We already have y^2 first, then y and finally y^0, so we don't have to rearrange anything.

Answer: y^2-6y+8

2.

(6y^2)(-8x^3-y+5)

Multiply all terms on the right with 6y^2:

6y^2 * -8x^3 + 6y^2 * -y + 6y^2 * 5\\-48x^3y^2 - 6y^3 + 30y^2

Not sure which order is preferred here, you can put either the y^3 term first or x^3y^2.

Answer: -6y^3 - 48x^3y^3 + 30y^2

3.

2x^4(8x^5-7x+10)

Multiply all terms in the right parenthesis with 2x^4 :

2x^4 * 8x^5 + 2x^4 * -7x + 2x^4 * 10\\16x^9 -14x^5 + 20x^4

Answer: 16x^9 -14x^5 + 20x^4

4.

(7x+3)(2x-4)

First, multiply all terms on the right with 7x. Then do the same with 3.

7x * 2x + 7x*-4 + 3*2x + 3*-4\\14x^2 - 28x + 6x -12\\14x^2 - 22x - 12

Answer: 14x^2-22x-12

5.

(3x+4y)^2

(3x+4y)(3x+4y)

Multiply all terms on the right with 3x, then do the same with 4y:

3x*3x + 3x*4y + 4y*3x + 4y*4y\\9x^2 + 12xy + 12xy + 16y^2\\9x^2 + 24xy + 16y^2

Here, I choose to rearrange them to x^2, then y^2, then xy:

Answer: 9x^2+16y^2 + 24xy

6.

-5x^6(x^3+xy-2y^2)

Like previous similar ones, we multiply all terms in the parenthesis with -5x^6:

-5x^6 * x^3 -5x^6 * xy -5x^2*-2y^2\\-5x^9 - 5x^7y +10x^2y^2

Answer: -5x^9 - 5x^7y +10x^2y^2

7.

(-x^2y)(5x^3+4x^2y+5y^4)

Multiply all terms in the right parenthesis with -x^2y:

-x^2y*5x^3 -x^2y*4x^2y -x^2y*5y^4\\-5x^5y - 4x^4y^2 - 5x^2y^5

Here, you can also choose which order you believe is appropriate.

Answer: -5x^5y - 4x^4y^2 - 5x^2y^5

8.

(7x-3y)(-2x+5y)

Multiply the terms on the right with 7x, then with -3y:

7x*-2x + 7x*5y -3y*-2x-3y*5y\\-14x^2 + 35xy +6xy - 15y^2\\-14x^2 + 41xy - 15y^2

Answer: -14x^2 + 41xy - 15y^2

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What number or fractions are between 2/3 and 1 1/3
olganol [36]
To find the fraction inbetween,
1. Add up the 2 fractions
2 Divide it by 2

Step (!) Add them up:
2/3 + 1 1/3 = 2

Step (2) Divide the answer by 2:
2÷ 2 = 1

Answer: The number between 2/3 and 1 1/3 is 1.
5 0
3 years ago
carley beat the school record for the 400 meter run by 1.3 seconds. if she ran the race in 55.7 seconds what was the record?
Vika [28.1K]

Answer:

If Carley ran the 400 meter run in a total of 55.7 seconds and she beat the record by 1.3 seconds, you would add 55.7 and 1.3

55.7+1.3= 57 seconds

The past school record for the girls 400 meter run was 57 seconds

Hope this helps ;)

4 0
3 years ago
Can u help me answer this I am confused.
Veronika [31]
If you read the graph it’s helps Uu better
8 0
3 years ago
He determines that 6 is an extraneous solution because the difference of the numerators is 6, so the 6s cancel to 0. which best
seropon [69]

The question is incomplete. Completed question is given below the answer.

His solution for x is correct, but in order for 6 to be an extraneous solution, one denominator has to result in 0 when 6 is substituted for x.

Given  

Then the solution follows thus:

Step 1: 8(x – 4) = 2(x + 2)

Step 2: 4(x – 4) = (x + 2)

Step 3: 4x – 16 = x + 2

Step 4: 3x = 18

Step 5: x = 6

It can be seen that his solution is correct. But 6 is not an extraneous solution.

An extraneous solution is a solution to an equation that emerges from the process of solving the problem but is not a valid solution to the original problem.

When 6 is substituted into the original equation, the original equation holds.

Therefore, his solution for x is correct, but in order for 6 to be an extraneous solution, one denominator has to result in 0 when 6 is substituted for x.

Learn more about extraneous solution here: brainly.com/question/3751209

#SPJ4

Completed question:-

A student solves the following equation for all possible values of x:His solution is as follows:

Step 1: 8(x – 4) = 2(x + 2)

Step 2: 4(x – 4) = (x + 2)

Step 3: 4x – 16 = x + 2

Step 4: 3x = 18

Step 5: x = 6

He determines that 6 is an extraneous solution because the difference of the numerators is 6, so the 6s cancel to 0.

Which best describes the reasonableness of the student’s solution?

His solution for x is correct and his explanation of the extraneous solution is reasonable.

His solution for x is correct, but in order for 6 to be an extraneous solution, both denominators have to result in 0 when 6 is substituted for x.

His solution for x is correct, but in order for 6 to be an extraneous solution, one denominator has to result in 0 when 6 is substituted for x.

His solution for x is incorrect. When solved correctly, there are no extraneous solutions.

5 0
2 years ago
The butter distributor charges $4.50 per pound, but there is a handling fee of $8.50 per order. Free shipping for orders between
kykrilka [37]

Answer:

14.00

Step-by-step explanation:

add

subtract

divide

multiple

4 0
2 years ago
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