Answer:
Step-by-step explanation:
S=student cost; T=teacher cost
.
32S+3T=$127 . Multiply this by 2.
64S+6T=$254 Subtract this below
.
25S+2T=$97.50 . Multiply this by 3.
75S+6T=$292.50
64S+6T=$254 . Subtract this (from above.)
.
11S=$38.50
S=$3.50
ANSWER 1: Student tickets cost $3.50.
.
32S+3T=$127
32($3.50)+3T=$127
$112+3T=$127
3T=$15
T=$5.00
ANSWER 2: Teacher tickets cost $5.00.
.
CHECK:
25S+2T=$97.50
25($3.50)+2($5.00)=$97.50
$87.50+$10.00=$97.50
$97.50=$97.50
8n- (2n-3) =12
8n-2n= 12+3
6n=15
n= 2.5
Hope this helps :)
9514 1404 393
Answer:
a) P(t) = 6.29e^(0.0241t)
b) P(6) ≈ 7.3 million
c) 10 years
d) 28.8 years
Step-by-step explanation:
a) You have written the equation.
P(t) = 6.29·e^(0.0241·t)
__
b) 2018 is 6 years after 2012.
P(6) = 6.29·e^(0.0241·6) ≈ 7.2686 ≈ 7.3 . . . million
__
c) We want t for ...
8 = 6.29·e^(0.0241t)
ln(8/6.29) = 0.0241t
t = ln(8/6.29)/0.0241 ≈ 9.978 ≈ 10.0 . . . years
__
d) Along the same lines as the calculation in part (c), doubling time is ...
t = ln(2)/0.0241 ≈ 28.7613 ≈ 28.8 . . . years
Answer:
208
Step-by-step explanation:
First let's find out what each container weighs..
Blue = 4 x 103 = 412
Red = 102 x 2 = 204
Now, Let subtract Blue container by Red Container..
412-204=208
Hence, the blue container weighs 208 more than the red container.
