Write the problem using exponents

Mathematics

2 answers:

Mila [183]3 years ago

8 0

Number one is 4^3
Number two is 2.6^4

sattari [20]3 years ago

7 0

4 to the 3 power 2.6 to the 4th power

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Plzzzzzzzzzzzz help me

grigory [225]

Answer:

y=-3/2x+6

Step-by-step explanation:

You can find the slope by taking two points on the graph, and making the one that occurs earlier in the graph (from left to right) the first point (x1, y1) and the one that occurs later in the graph the second point (x2, y2). The equation is m (or slope)=(y2-y1)/(x2-x1). I took the first two points in the table for this. m=(12-18)/-4-(-8)

the double negative on the bottom becomes an addition=> (12-18)/(-4+8)

the top simplifies to be -6 and the bottom simplifies to 4=>-6/4

this fraction can be reduced to -3/2, which is the slope of the graph.

Now, use point slope form (y-y1=m(x-x1)) to find the equation of the graph. Plug any coordinate on the graph in for x1 and y1 here. It should be correct as long as it is a point on the graph, but I am using the point (-8, 18) here.

=>y-18=-3/2(x-(-8))

the double negative in the parentheses becomes a positive=> y-18=-3/2(x+8)

distribute the -3/2 to every term in the parentheses=> y-18=-3/2x-12

add 18 to both sides, cancelling out the -18 on the left side of the equation=>y=-3/2x+6 (-12+18=6 to get 6 for b).

Therefore, the equation is y=-3/2x+6

6 0

2 years ago

A line that includes the point (0,0) has a slope of -9. What is its equation in slope-intercept

ikadub [295]

Y=-9x because y=mx+b is the formula so plug in the slope, m(-9) and the x-intercept, x(0)

3 0

2 years ago

What is the quotient of StartFraction 7 Superscript negative 1 Baseline Over 7 Superscript negative 2 Baseline EndFraction? Star

Komok [63]

The quotient of the number given number 7 Superscript negative 1 Baseline Over 7 Superscript negative 2 Baseline is 7.

<h3>What is the quotient?</h3>

Quotient is the resultant number which is obtain by dividing a number with another. Let a number a is divided by number b. Then the quotient of these two number will be,

$q=\dfrac{a}{b}$

Here, (<em>a, b</em>) are the real numbers.

The number StartFraction 7 Superscript negative 1 Baseline Over 7 Superscript negative 2 Baseline EndFraction, given can be written as,

$\dfrac{7^{-1}}{7^{-2}}$

Let the quotient of this division is n. Therefore,

$n=\dfrac{7^{-1}}{7^{-2}}$

A number in numerator of a fraction with negative exponent can be written in the denominator with the same but positive exponent and vise versa. Therefore,

$n=\dfrac{7^{2}}{7^{1}}\\n=7$