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yanalaym [24]
3 years ago
9

When he awakens he sneaks around the mess hall__________ than anyone can imagine ( cleverly)

Mathematics
1 answer:
Bingel [31]3 years ago
4 0

Answer:

smartly

Step-by-step explanation:

You might be interested in
4x-3(x-2)-x<br> I have 6. Is that correct?<br> 4x-3x-x=0<br> And -3*-2=6<br> 0+6=6
sesenic [268]
4x - 3(x - 2) - x
4x - 3x + 6 - x
4x - 4x + 6
6....u r correct because ur x's cancel out
8 0
2 years ago
Lets see who is smart lol
Simora [160]

9514 1404 393

Answer:

  \square\quad{y=\dfrac{1}{2}x+4}\\\\\square\quad{\dfrac{y-5}{x-2}=\dfrac{1}{2}}

Step-by-step explanation:

The slope of a line is the same everywhere, so an equation can be written making use of that fact.

  \dfrac{y-y_1}{x-x_1}=\dfrac{y_2-y_1}{x_2-x_1}\\\\\dfrac{y-5}{x-2}=\dfrac{7-5}{6-2}=\dfrac{2}{4}\\\\\boxed{\dfrac{y-5}{x-2}=\dfrac{1}{2}}

Cross-multiplying gives ...

  2(y -5) = x -2

  2y -10 = x -2  . . . eliminate parentheses

  2y = x +8 . . . . . . . add 10; next, divide by 2

  \boxed{y=\dfrac{1}{2}x+4}

__

These equations match choices B and D.

6 0
2 years ago
5 3/2 x 3 6/7 you have 10 point to do the answer
pogonyaev

Step-by-step explanation:

Conversion a mixed number 5 3/2

to an improper fraction: 5 3/2 = 5 3/2

= 5 · 2 + 3/2

= 10 + 3/2

= 13/2

To find a new numerator:

a) Multiply the whole number 5 by the denominator 2. Whole number 5 equally 5 * 2/2

= 10/2

b) Add the answer from previous step 10 to the numerator 3. New numerator is 10 + 3 = 13

c) Write a previous answer (new numerator 13) over the denominator 2.

Five and three halfs is thirteen halfs

Conversion a mixed number 3 6/7

to an improper fraction: 3 6/7 = 3 6/7

improper fraction: 3 6/7 = 3 6/7

3 · 7 + 6/7 = 21 + 6/7 =27/7

To find a new numerator:

a) Multiply the whole number 3 by the denominator 7. Whole number 3 equally 3 * 7/7

= 21/7

b) Add the answer from previous step 21 to the numerator 6. New numerator is 21 + 6 = 27

c) Write a previous answer (new numerator 27) over the denominator 7.

Three and six sevenths is twenty-seven sevenths

Multiple:

13/2 * 27/7 = 13/2 · 27/7 = 351/14

3 0
2 years ago
Choose the correct description of the graph of the compound inequality: x − 2 &gt; −3 and 3x less than or equal to 12
STALIN [3.7K]
<span>X - 2 > -3 x > -3 + 2 x > -1 A number line with an open circle -1, closed circle on 4 and shading in between.,when dividing/multiplying by a negative, the inequality sign changes. An open circle is used when there is no equal sign involved. A closed circle is used when there is an equal sign involved. If it is greater then, shading goes to the right. If it is less then, shading goes to the left</span>
4 0
2 years ago
Read 2 more answers
I need help w/ this!! thank you
Fittoniya [83]
<h3><u>Answer:</u></h3>

\boxed{\pink{\sf \leadsto Yes \ there \ is \ a \ solution \ of \ the \ given \ inequality .}}

<h3><u>Step-by-step explanation:</u></h3>

A inequality is given to us and we need to convert it into standard form and see whether if it has a solution . So let's solve the inequality.

The inequality given to us is :-

\bf\implies |2y + 3 | - 1 \leq 0 \\\\\bf\implies |2y+3|\leq 1 \\\\\bf\implies (|2y+3|)^2 \leq 1^2  \\\\\bf\implies (2y+3)^2 \leq 1  \\\\\bf\implies (2y)^2+3^2+2(2y)(3) \leq 1  \\\\\bf\implies 4y^2+9+12y - 1 \leq 0  \\\\\bf\implies 4y^2+12y+8 \leq 0 \\\\\bf\implies 4( y^2 + 3y + 2 ) \leq 0  \\\\\bf\implies y^2+3y +2 \leq 0 \:\:\bigg\lgroup \purple{\bf Standard \ form \ of \ inequality }\bigg\rgroup   \\\\\bf\implies y^2y+2y+y+2 \leq 0  \\\\\bf\implies y(y+2)+1(y+2)\leq 0  \\\\\bf\implies ( y+2)(y+1)\leq 0  \\\\\bf\implies \boxed{\red{\bf y \leq (-2) , (-1) }}

Let's plot a graph to see its interval . Graph attached in attachment .

Now we can see that the Interval notation of would be ,

\boxed{\boxed{\orange \tt \purple{\leadsto}y \in [-2,-1] }}

<h3><u>Hence</u><u> the</u><u> </u><u>standa</u><u>rd</u><u> </u><u>form</u><u> </u><u>of</u><u> </u><u>inequa</u><u>lity</u><u> </u><u>is</u><u> </u><u>y²</u><u>+</u><u>3y</u><u> </u><u>+</u><u>2</u><u> </u><u>≤</u><u> </u><u>0</u><u> </u><u>and</u><u> </u><u>the </u><u>Solution</u><u> </u><u>set</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>ineq</u><u>uality</u><u> </u><u>is</u><u> </u><u>[</u><u> </u><u>-</u><u>2</u><u> </u><u>,</u><u> </u><u>-</u><u>1</u><u> </u><u>]</u><u> </u><u>.</u></h3>
4 0
2 years ago
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