I: 12x-5y=0
II:(x+12)^2+(y-5)^2=169
with I:
12x=5y
x=(5/12)y
-> substitute x in II:
((5/12)y+12)^2+(y-5)^2=169
(25/144)y^2+10y+144+y^2-10y+25=169
(25/144)y^2+y^2+10y-10y+144+25=169
(25/144)y^2+y^2+144+25=169
(25/144)y^2+y^2+169=169
(25/144)y^2+y^2=0
y^2=0
y=0
insert into I:
12x=0
x=0
-> only intersection is at (0,0) = option B
#4) From the reference angle of 58° we can see that we have the side opposite to that angle as well as the hypotenuse. Recall that sin=opp/hyp so we are going to use sine to find that side
sin(58°) =

(multiply both sides by 19 to isolate x)
19 sin(58°) = x (plug into calculator)
16.1 = x
#5) From the reference angle of 56°, we see that we have the adjacent and the opposite sides. Remember that tan=opp/adj so we will use tangent to find x
tan(56°) =

(multiply both sides by

)

(flip them so x is on the top)
[tex] \frac{12}{tan(56)} = x
8.1 = x
Answer:
50 1/6% (50 and one sixth) or $22.92
Step-by-step explanation:
Answer:
3.1
4.2
5.2
42
Step-by-step explanation: Just copy the other cone and find half of the diameter to find the radius the cones are congruent.