y = 7 + 3x
y = 3x + 7
y = mx + b, therefore the y-intercept is 7.
3y = 6x + 12
y = 2x + 4
y = mx + b, therefore the y-intercept is 4.
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Answer:x = 2
y = 5
Explanation:ABCD is a parallelogram. This means that each two opposite sides are equal.
This means that:1- AB = CD2y + 1 = 7x - 3 ...........> equation I
2- AD = BC3x = y + 1
This can be rewritten as:y = 3x - 1............> equation II
Substitute with equation II in equation I and solve for x as follows:2y + 1 = 7x - 3 ...........> equation I
2(3x - 1) + 1 = 7x - 3
6x - 2 + 1 = 7x - 3
6x - 1 = 7x - 3
7x - 6x = -1 + 3
x = 2
Substitute with x in equation I to get y as follows:y = 3x - 1
y = 3(2) - 1
y = 6 - 1
y = 5
Hope this helps :)
Answer:
Step-by-step explanation:
Take a triangle ABC, in which AB=AC.
Construct AP bisector of angle A meeting BC at P.
In ∆ABP and ∆ACP
AP=AP[common]
AB=AC[given]
angle BAP=angle CAP[by construction]
Therefore, ∆ABP congurent ∆ACP[S.A.S]
This implies, angle ABP=angleACP[C.P.C.T]
Answer:
(5, 0 )
Step-by-step explanation:
Given the 2 equations
y = x² - 2x - 15 → (1)
y = 8x - 40 → (2)
Substitute y = x² - 2x - 15 into (2)
x² - 2x - 15 = 8x - 40 ( subtract 8x - 40 from both sides )
x² - 10x + 25 = 0 ← in standard form
(x - 5)² = 0 ← in factored form, thus
x - 5 = 0 ⇒ x = 5
Substitute x = 5 into (2) for corresponding value of y
y = 8(5) - 40 = 40 - 40 = 0
Solution is (5, 0 )