5 x minus 10 y = 30 what is the first step to find x

The answer to this

andrew11 [14]

Answer:

28

Step-by-step explanation:

90 - 62=28

6 0

3 years ago

Give an example of an equation whose solution is 5

Ray Of Light [21]

Answer:

x - 5 = 0

Step-by-step explanation:

x - 5 = 0

Add 5 on both sides,

x - 5 + 5 = 0 + 5

x = 5

The equation whose solution is 5,

" x - 5 = 0 "

6 0

2 years ago

Read 2 more answers

Factor using special products 9/16 a2−2ab+ 16/9 b2

almond37 [142]

Answer:

Answer is given below with explanations. 

Step-by-step explanation:

$Given \: question \: is \\ \frac{9}{16} {a}^{2} - 2ab + \frac{16}{9 } {b}^{2} \\ { (\frac{3}{4}a) }^{2} - 2ab + {( \frac{4}{3}b )}^{2} \\ \\ (\frac{3}{4} a + \frac{4}{3} b)^2 \\$

HAVE A NICE DAY!

THANKS FOR GIVING ME THE OPPORTUNITY TO ANSWER YOUR QUESTION. 

5 0

3 years ago

Justin watched 4/8 of his movie before dinner and 1/8 of his movie after dinner how much of his movie does he have left to watch

saw5 [17]

Answer:

3/8 of the movie

Step-by-step explanation:

4/8 + 1/8 = 5/8

8/8 - 5/8 = 3/8

7 0

3 years ago

Read 2 more answers

Consider a binomial experiment with n = 10 and p = 0.10. (a) Compute f(0). If required, round your answer to four decimal places

ss7ja [257]

Answer:

(a) The value of f (0) is 0.3487.

(b) The value of f (2) is 0.1937.

(c) The value of P (X ≤ 2) is 0.9298.

(d) The value of P (X ≥ 1) is 0.6513.

(e) The value of E (X) is 1.

(f) The value of V (X) is 0.9 and σ is 0.9487.

Step-by-step explanation:

The random variable X follows a Binomial distribution with parameter n = 10 and p = 0.10.

The probability mass function of X is:

$P(X=x)={10\choose x}0.10^{x}(1-0.10)^{10-x};\ x=0,1,2,3...$

(a)

Compute the value of f (0) as follows:

f (0) = P (X = 0)

$={10\choose 0}0.10^{0}(1-0.10)^{10-0}\\=1\times 1\times 0.348678\\=0.348678\\\approx0.3487$

Thus, the value of f (0) is 0.3487.

(b)

Compute the value of f (2) as follows:

f (2) = P (X = 2)

$={10\choose 2}0.10^{2}(1-0.10)^{10-2}\\=45\times 0.01\times 0.43047\\=0.1937115\\\approx0.1937$

Thus, the value of f (2) is 0.1937.

(c)

Compute the value of P (X ≤ 2) as follows:

P (X ≤ 2) = P (X = 0) + P (X = 1) + P (X = 2)

$=\sum\limits^{0}_{2} {{10\choose x}0.10^{x}(1-0.10)^{10-x}}\\=0.3487+0.3874+0.1937\\=0.9298$

Thus, the value of P (X ≤ 2) is 0.9298.

(d)

Compute the value of P (X ≥ 1) as follows:

P (X ≥ 1) = 1 - P (X < 1)

= 1 - P (X = 0)

= 1 - 0.3487

= 0.6513

Thus, the value of P (X ≥ 1) is 0.6513.

(e)

Compute the expected value of X as follows:

$E(X)=n\times p$

$=10\times 0.10\\=1$

Thus, the value of E (X) is 1.

(f)

Compute the variance of X as follows:

$V(X)=np(1-p)$

$=10\times 0.10\times (1-0.10)\\=0.90$

Compute the standard deviation of X as follows:

$SD(X)=\sqrt{V(X)}$

$=\sqrt{0.90}\\=0.94868\\\approx0.9487$

Thus, the value of V (X) is 0.9 and σ is 0.9487.

8 0

4 years ago