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Musya8 [376]
3 years ago
10

5 x minus 10 y = 30 what is the first step to find x

Mathematics
1 answer:
chubhunter [2.5K]3 years ago
3 0
Move X to the other side with the 30.
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At time t= 0, Elevator A is 40 feet above the ground floor.
Zepler [3.9K]

There is no graph for Elevator B. I'm sorry if I'm mistaken.

7 0
3 years ago
Solve for x. <br><br> −1/5x≥−2
Rzqust [24]

Answer:

x ≤ -10

Step-by-step explanation:

distribute -2 into your denominator (5)

7 0
4 years ago
En el estante de un negocio hay 2 tipos de tarros de la misma mermelada y marca. El tarro más alto tiene el doble de altura que
Ipatiy [6.2K]

Answer:

tarro corto

Step-by-step explanation:

Aquí tenemos que comprar el frasco que tiene el menor costo por volumen.

h_1 = Altura del frasco corto

h_2 = La altura del frasco alto es el doble que el del frasco corto. = 2h_1

d_1 = Diámetro del frasco corto

d_2 = El diámetro del frasco alto es la mitad del frasco corto = \dfrac{1}{2}d_1

El volumen de un cilindro es \pi \dfrac{d^2}{4}h

La razón de los volúmenes de los frascos es

\dfrac{V_1}{V_2}=\dfrac{\pi\dfrac{d_1^2}{4}h_1}{\pi\dfrac{d_2^2}{4}h_2}\\\Rightarrow \dfrac{V_1}{V_2}=\dfrac{d_1^2h_1}{d_2^2h_2}\\\Rightarrow \dfrac{V_1}{V_2}=\dfrac{d_1^2h_1}{(\dfrac{1}{2}d_1)^22h_1}\\\Rightarrow \dfrac{V_1}{V_2}=\dfrac{d_1^2h_1}{\dfrac{1}{4}d_1^22h_1}\\\Rightarrow \dfrac{V_1}{V_2}=\dfrac{1}{\dfrac{1}{2}}\\\Rightarrow \dfrac{V_1}{V_2}=2\\\Rightarrow V_1=2V_2

El costo del frasco corto por unidad de volumen es

\dfrac{8000}{V_1}=\dfrac{8000}{2V_2}=\dfrac{4000}{V_2}

El costo del frasco alto por unidad de volumen es

\dfrac{4500}{V_2}=\dfrac{4500}{V_2}

\dfrac{4000}{V_2}

Entonces, el costo del frasco corto por unidad de volumen es menor que el costo por unidad de volumen del frasco alto.

Por lo tanto, deberíamos tomar el frasco corto.

5 0
3 years ago
Complete the dilation centered at A with a scale factor of 1/2.
ElenaW [278]

Answer:

A'=(5/2,-5/2)

therefore A'(2.5,-2.5)

Step-by-step explanation:

8 0
3 years ago
50 POINTS!! HELP!
Minchanka [31]

i dont have time to do all of it (sorry)

but this is how you do the point and slope questions:

use the equation: y-y1 = m(x - x1)

y1 is the y point you are given

x1 is the x point you are given

m is your slope

substitute all of those in from the question

the first one is:

y --4 = -5/6(x-8)

-- turns into a plus so the answer would be

y+4 = -5/6(x-8)

6 0
3 years ago
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