Answer:
there would be <u>8</u><u> </u><u>sides</u> if there are 20 diagonals
Answer:
What you need help with? I don't see a question or anything
Step-by-step explanation:
X+y+5=0
y=-x-5
If a solution exists y=y so we can say
x^2-9x+10=-x-5 add x+5 to both sides
x^2-8x+15=0 now factor
x^2-3x-5x+15=0
x(x-3)-5(x-3)
(x-5)(x-3) so x=3 and 5, using y=-x-5
y(3)=-8 and y(5)=-10
So the two solutions are:
(3,-8) and (5,-10)
Answer:
c
Step-by-step explanation:
Answer:
6) The answer is 210p - 105
7) The answer is -124q + 216
Step-by-step explanation:
1. Always Distributive Property first
6) -14 (8 - 15p) 7) -12 ( -18 + 10q)
-112 +210p 216 -120q
2. Combine like terms
6) -112 + 7 = -105 your full answer is 210p -105
7) -120q + -4q = -124q Your full answer is -124q +216.
Hope this helps.
