Question

From the top of a vertical tower 248 m high , a stone is projected vertically downwards with a speed of 8 ms . After x seconds another stone is projected vertically upwards from the level of the base of the tower with a speed 25 ms . Given that two stones are at same height moving in the same direction 6 seconds after projection of the first stone , calculate :
1) value of x
2) the velocity of the second stone at this instant

Answer 1

It is 2 that what i got and i think i got it write if not delete