the data represents the heights of fourteen basketball players, in inches. 69, 70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77, 8
Daniel [21]
If you would like to know the interquartile range of the new set and the interquartile range of the original set, you can do this using the following steps:
<span>The interquartile range is the difference between the third and the first quartiles.
The original set: </span>69, 70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77, 82
Lower quartile: 72
Upper quartile: 76.25
Interquartile range: upper quartile - lower quartile = 76.25 - 72 = <span>4.25
</span>
The new set: <span>70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77
</span>Lower quartile: 72.5
Upper quartile: 76
Interquartile range: upper quartile - lower quartile = 76 - 72.5 = 3.5
The correct result would be: T<span>he interquartile range of the new set would be 3.5. The interquartile range of the original set would be more than the new set.</span>
Answer:
D
Step-by-step explanation:
4x^4+3x^2-3x^3-3x+1
Answer:
The correct answer is
(x + 2) (x + 1) (x - 3)
Step-by-step explanation:
Answer:I want to go to school
Step-by-step explanation:because it is way eaiser
22. 30 degrees because line DB bisects(meaning cuts in half) angle ABC so DBC should be 30 degrees because 30+30 is 60 which is what angle ABC is.
23. 60 degrees because if we assume that it is a parallelogramand that the opposite angle are congruent.
24. 120 degrees because a quadrilatteral has sides that will equal to 360 degrees, and I said that a parallelogram will have its opposite angles congruent we take away 120 from 360 (from the previous angles ABC and BCD) we end up with 240, we divide 240 by 2 and end up with 120 degrees
25. 60 degrees. I found that angle DCB is 120 degrees so angles DCB and DCE are supplementary(add up to 180 degrees) and we subtract 120 from 180 which is 60 degrees.
26. 60 degrees vertical to angle DCE.
27. 120 degrees supplementary to DCE
