-12=4(x-7)-8x
One solution was found :
x = -4
Rearrange:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
-12-(4*(x-7)-8*x)=0
Step by step solution :
Step 1 :
Equation at the end of step 1 :
-12 - (4 • (x - 7) - 8x) = 0
Step 2 :
Step 3 :
Pulling out like terms :
3.1 Pull out like factors :
4x + 16 = 4 • (x + 4)
Equation at the end of step 3 :
4 • (x + 4) = 0
Step 4 :
Equations which are never true :
4.1 Solve : 4 = 0
Hope this helps you, Have a nice day.
From the information: v is 64 while c is 5
Differentiate the new equation h=-16
+ 64t + 5 to get 
= -32t + 64.
no 13). At maximum height this derivative equals zero so: -32t + 64 = 0; -32t = -64; t=2.Hence ans is 2 secs
no 14). put t as 2 sec in the equation: h=-16 + 64t + 5. This gives
h=-16( 
) + 64(2) + 5; h=-64+128+5=69. Hence h is 69ft
Which is an arithmetic sequence?A)9, 12, 16, 20...B)9, 11, 13, 16...C)1, 5, 9, 13, 17...D)12, 14, 16, 18...
marta [7]
Answer: https://www.khanacademy.org/commoncore/grade-HSF-F-IF#HSF-IF.A.3
Step-by-step explanation:
copy and paste the link on to your search bar
Let V, be the rate in still water and let C = rate river current
If the boat is going :
upstream, its rate is V-C and if going
downstream, its rate is V+C,
But V = 5C, then
Upstream Rate: 5C - C = 4 C
Downstream rate: 5C+C = 6C
Time = distance/Rate, (or time = distance/speed) , then:
Upstream time 12/4C and
Downstream time: 12/.6C
Upstream time +downstream time:= 2h30 ' then:
12/4C + 12/.6C = 2.5 hours
3/C + 2/C = 5/2 (2.5 h = 5/2)
Reduce to same denominator :
5C = 10 and Rate of the current = 2 mi/h
