Let y = 3^x , then 9^x = (3^2)^x = (3^x)^2 = y^2, so we can write the equation as
y^2 - 10y + 9 = 0
(y - 9)(y - 1) = 0
giving y = 9 or y = 1
Therefore 3^x = 9 giving x = 2
and 3^x = 1 giving x = 0
so the solution set is {0, 2}
Note - I have assumed that the 'x' after the 10 means 'multiply'. Is that correct?
Answer:
Step-by-step explanation:
x (3,7,11,15)
y (4,6,8,10)
A. This IS a function because u have no repeating x values
B. Data in table :
when x = 11, y = 8
relation : f(x) = 5x - 21....when x = 11
f(11) = 5(11) - 21
f(11) = 55 - 21
f(11) = 34.....so when x = 11, y = 34
therefore, the relation f(x) = 5x - 21 has a greater value then the table
C. f(x) = 5x - 21......f(x) = 99
99 = 5x - 21
99 + 21 = 5x
120 = 5x
120/5 = x
24 = x <====
I think it’s
x= -54
PLZZ GIVE BRAINLYEST
Answer:
x=80, y=15
Step-by-step explanation:
The angle on the opposite side of 100 will be equal to x
We know it is 180-100 so x=80
We know 6y=90
therfore y = 90/6 which equals 15
so y=15 and x=80
Distribution is multiplying. So
6(12)-6(5)
72-30
42
