Write an equation in standard firm using integers y-4=5(x-8)

Mathematics

1 answer:

diamong [38]3 years ago

3 0

I would say its y=5x-36

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Find derivative: ^6 square root x^5

SVEN [57.7K]

$\large\begin{array}{l} \textsf{Find the derivative of}\\\\ \mathsf{f(x)=\,^6\!\!\!\sqrt{x^5}}\qquad\qquad\textsf{(expressing it as a power...)}\\\\ \mathsf{f(x)=x^{\frac{5}{6}}} \end{array}$

$\large\begin{array}{l} \textsf{So you can use the power rule to differentiate it:}\\\\ \mathsf{f'(x)=\big(x^{\frac{5}{6}}\big)'}\\\\ \mathsf{f'(x)=\dfrac{5}{6}\,x^{\frac{5}{6}-1}}\\\\ \mathsf{f'(x)=\dfrac{5}{6}\,x^{\frac{5}{6}-\frac{6}{6}}} \end{array}$

$\large\begin{array}{l} \mathsf{f'(x)=\dfrac{5}{6}\,x^{\frac{5-6}{6}}}\\\\ \mathsf{f'(x)=\dfrac{5}{6}\,x^{-\,\frac{1}{6}}}\\\\ \mathsf{f'(x)=\dfrac{5}{6}\cdot \dfrac{1}{x^{\frac{1}{6}}}}\\\\ \mathsf{f'(x)=\dfrac{5}{6x^{\frac{1}{6}}}}\\\\\\ \boxed{\begin{array}{c}\mathsf{f'(x)=\dfrac{5}{6\,^6\!\!\!\sqrt{x}}} \end{array}}\qquad\checkmark \end{array}$

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$\large\textsf{I hope it helps. :-)}$

Tags: <em>derivative sixth root irrational function power rule differential calculus</em>

3 0

3 years ago

PLEASE HELP ASAAAPPPPPP

Ad libitum [116K]

A) 276 / 138 = 2

B) 26/2 = 13, 13/2 = 6.5

Answer is B

7 0

3 years ago

Solve by substitution-5x+4y=22 x - 3y = 0A) No solution.

zepelin [54]

We want to use substitution to solve
-5x + 4y = 22 (1)
x - 3y = 0 (2)

From (2), obtain
x = 3y (3)
Substitute (3) into (1).
-5(3y) + 4y = 22
-15y + 4y = 22
-11y = 22
y = -2
From (3), obtain
x = 3y = 3*(-2) = -6

Answer: e. (-6, -2)

5 0

2 years ago

What is true about the hypotenuse?

Temka [501]

Answer:

All of the above

Step-by-step explanation:

In Pythagorean Theorem, a and b are the short and long leg, and c is the hypotenuse.

5 0

2 years ago

Read 2 more answers

30 POINTS NO CAP PLEASE HELP NEED RIGHT ANSWER