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grin007 [14]
3 years ago
5

Write an equation in standard firm using integers y-4=5(x-8)

Mathematics
1 answer:
diamong [38]3 years ago
3 0
I would say its y=5x-36
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Is 0.93 less than 1?
bonufazy [111]

Answer:

yes

Step-by-step explanation:

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I need to know which answer this is...​
charle [14.2K]
I would go with C :)
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Errors in an experimental transmission channel are found when thetransmission is checked by a certifier that detects missing pul
irina1246 [14]

Answer:

As shown below

Step-by-step explanation:

Given that when X denotes the errors in an experimental transmission channel, when checked by a certifier that detects missing pulses. follows the cumulative density function as given below:

F(x) = 0, 0

(a) P(X \leq  4) =F(4) = 0.9\\(b) P(X > 7)=1-F(8) = 0\\(c) P(X \leq  5)=F(6) = 0.9 \\(d) P(X> 4)=1-F(4)=1-0.9=0.1 \\(e) P(X \leq  2)=F(3) = 0.7

6 0
3 years ago
In a list of households, own homes and do not own homes. Five households are randomly selected from these households. Find the p
hichkok12 [17]

Answer:

The probability of success for this case would be:

p =\frac{9}{15}= 0.6 representing the proportion of homes that are own homes

Let X the random variable of interest, on this case we now that:  

X \sim Binom(n=15, p=0.6)  

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

And we want this probability:

P(X=3)

And uing the probability mass function we got:

P(X=3)= 15C3 (0.6)^3 (1-0.6)^{15-3}= 0.00165

Step-by-step explanation:

Adduming the following info: In a list of 15 households, 9 own homes and 6 do not own homes. Five households are randomly selected from these 15 households. Find the probability that the number of households in these 5 own homes is exactly 3.

Round your answer to four decimal places

P (exactly 3)=

Previous concepts  

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".  

Solution to the problem

The probability of success for this case would be:

p =\frac{9}{15}= 0.6 representing the proportion of homes that are own homes

Let X the random variable of interest, on this case we now that:  

X \sim Binom(n=15, p=0.6)  

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

And we want this probability:

P(X=3)

And uing the probability mass function we got:

P(X=3)= 15C3 (0.6)^3 (1-0.6)^{15-3}= 0.00165

4 0
3 years ago
25 x 170 x 6.350<br> please help
m_a_m_a [10]

Answer:

26,987.5

Step-by-step explanation:

hope it's helpful to you ☺️

\sf{}

♛┈⛧┈┈•༶♛┈⛧┈┈•༶

✌️

8 0
2 years ago
Read 2 more answers
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