It looks like you already have a common denominator (y^2-9). So, you can just add the two numerators and put that over the common denominator. Hope this helps!
11x+2 = 9x+6. Subtract 2 from both sides. 11x = 9x+6. subtract 9x from both sides. 2x = 4, divide both sides by 2. x = 2. Substitute the x with 2 and check to see it it works. The numbers should equal each other.
<span>If lim(x->3) f(x)=7, then </span><span>f(3) = 7.</span>
Answer:
20 dimes and 2 quarters
Step-by-step explanation:
x = number of dimes
y = number of quarters
minimum is greater than or equal to ≥
x+y ≥16
no more than is less than or equal to ≤ ,
value of dime is $ 0.10
value of quarter is $0.25 so
0.10x + 0.25y ≤ 3.00
Rewrite inequalities in terms of y:
y ≥16 - x
(0.25/0.25)y ≤ (3.00/0.25)-(0.10/0.25)x→
y≤12 - 0.4x
Graph system: see file