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3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Mathematics

2 answers:

sasho [114]3 years ago

6 0

Answer:

0.80

This is the correct answer! I just took the test! Good luck!!!

denis-greek [22]3 years ago

4 0

Answer: 0.80

Step-by-step explanation:

P (2 ≤ x ≤ 4) is: P(X = 2) + P(X = 3) + P(X = 4)

= 0.36 + 0.12 + 0.32

= 0.48 + 0.32

= 0.80

It can also be calculated as: 1 - P(X = 1)

= 1 - 0.20

= 0.80

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A certain region currently has wind farms capable of generating a total of 2200 megawatts (2.2 gigawatts) of power. Assuming win

sveta [45]

Answer:

The correct answer is A. 4,818'000,000 kilowatt-hours per year and B. 481,800 households.

Step-by-step explanation:

1. Let's review the information provided to us for solving the questions:

Power capacity of the wind farms = 2,200 Megawatts or 2.2 Gigawatts

2. Let's resolve the questions A and B:

Part A

Assuming wind farms typically generate 25% of their capacity, how much energy, in kilowatt-hours, can the region's wind farms generate in one year?

2,200 * 0.25 = 550 Megawatts

550 Megawatts = 550 * 1,000 Kilowatts = 550,000 Kilowatts

Now we calculate the amount of Kilowatts per hour, per day and per year:

550,000 Kw generated by the farms means that are capable of produce 550,000 kw per hour of energy

550,000 * 24 = 13'200,000 kilowatt-hours per day

13'200,000 * 365 = 4,818'000,000 kilowatt-hours per year

Part B

Given that the average household in the region uses about 10,000 kilowatt-hours of energy each year, how many households can be powered by these wind farms?

For calculating the amount of households we divide the total amount of energy the wind farms can generate (4,818'000,000 kilowatt-hours) and we divide it by the average household consumption (10,000 kilowatt-hours)

Amount of households = 4,818'000,000/10,000 = 481,800

8 0

3 years ago

How do you square a variable

77julia77 [94]

To square means to multiply something by itself. A variable is a letter such as x. So a squared variable=x×x=x^2.
I hope that helped.

8 0

3 years ago

Air containing 0.04% carbon dioxide is pumped into a room whose volume is 6000 ft3. The air is pumped in at a rate of 2000 ft3/m

borishaifa [10]

Answer:

the concentration at 10 minutes= 0.4+0.0133= 0.4133%

Step-by-step explanation:

Air containing 0.04% carbon dioxide

V, volume of room is 6000 ft3.

Q, rate of air 2000 ft3/min,

initial concentration of 0.4% carbon dioxide,

determine the subsequent amount in the room at any time.

What is the concentration at 10 minutes?

firstly, we find the time taken for air to completely filled the room

Q = V/t

t = V/Q = 6000/2000 = 3min

so, its take 3mins for air to be completely filled in the room and for exhaust air to move out.

there is an initial concentration of 0.4% carbon dioxide, and the air pump in is 0.04%.

therefore,

3mins = 0.04% of CO2

3*60 =180sec = 0.04%

1sec = 0.04/180 = 0.00022%/sec

so at any time the concentration of CO2 is 0.4 + 0.00022 =0.40022%/sec

What is the concentration at 10 minute

the concentration at 10minutes = the concentration for 1minute because at every minutes, the concentration moves in is moves out. = concentration for 2000ft3.

for 0.04% = 6000ft3

? = 2000ft3

= 2000* 0.04)/6000 =0.0133%

the concentration at 10 minutes= 0.4+0.0133= 0.4133%

4 0

3 years ago

On any given day, mail gets delivered by either Alice or Bob. If Alice delivers it, which happens with probability 1/4 , she doe

Troyanec [42]

Answer:

(a) The value of fₓ (9.5) is 0.125.

(b) The value of fₓ (10.5) is 0.50.

Step-by-step explanation:

Let X denote delivery time of the mail delivered by Alice and Y denote delivery time of the mail delivered by Bob.

It i provided that:

$X\sim U(9, 11)\\Y\sim U(10, 12)$

The probability that Alice delivers the mail is, p = 1/4.

The probability that Bob delivers the mail is, q = 3/4.

The probability density function of a Uniform distribution with parameters [a, b] is:

$f(x)=\left \{ {{\frac{1}{b-a};\ a, b>0} \atop {0;\ otherwise}} \right.$

The probability density function of the delivery time of Alice is:

$f(X_{A})=\left \{ {{\frac{1}{b-a}=\frac{1}{2};\ [a, b]=[9, 11]} \atop {0;\ otherwise}} \right.$

The probability density function of the delivery time of Bob is:

$f(X_{B})=\left \{ {{\frac{1}{b-a}=\frac{1}{2};\ [a, b]=[10, 12]} \atop {0;\ otherwise}} \right.$

(a)

Compute the value of fₓ (9.5) as follows:

For delivery time 9.5, only Alice can do the delivery because Bob delivers the mail in the time interval 10 to 12.

The value of fₓ (9.5) is:

$f_{X}(9.5)=p.f(X_{A})+q.f(X_B})\\=(\frac{1}{4}\times \frac{1}{2})+(\frac{3}{4}\times0)\\=\frac{1}{8}\\=0.125$

Thus, the value of fₓ (9.5) is 0.125.

(b)

Compute the value of fₓ (10.5) as follows:

For delivery time 10.5, both Alice and Bob can do the delivery because Alice's delivery time is in the interval 9 to 11 and that of Bob's is in the time interval 10 to 12.

The value of fₓ (10.5) is:

$f_{X}(10.5)=p.f(X_{A})+q.f(X_B})\\=(\frac{1}{4}\times \frac{1}{2})+(\frac{3}{4}\times\frac{1}{2})\\=\frac{1}{8}+\frac{3}{8}\\=0.50$

Thus, the value of fₓ (10.5) is 0.50.

5 0

3 years ago

Find the volume of the cubes or rectangular prisms in cubic centimeters.

DanielleElmas [232]

a) Volume of Rectangular prism is $\frac{36}{125}\,\,cm^3$

b) Volume of cube is $\frac{8}{125}\,\,cm^3$

c) Volume of cube is $\frac{1}{125}\,\,cm^3$

d) Volume of Rectangular prism is $\frac{6}{125}\,\,cm^3$

Step-by-step explanation:

Part a)

Volume of rectangular prism with

length= $\frac{3}{5}\,\,cm$

width= $\frac{4}{5}\,\,cm$

height = $\frac{3}{5}\,\,cm$

The formula used to find Volume of rectangular prism is:

$Volume\,\,of\,\,rectangular\,\,prism=length*width*height$

Putting values:

$Volume\,\,of\,\,rectangular\,\,prism=\frac{3}{5} *\frac{4}{5} *\frac{3}{5}\\Volume\,\,of\,\,rectangular\,\,prism=\frac{36}{125}\,\,cm^3$

So, Volume of Rectangular prism is $\frac{36}{125}\,\,cm^3$

Part b)

Volume of cube with side length of $\frac{2}{5}\,\,cm$

The formula used to find Volume of cube is:

$Volume\,\,of\,\,cube=length^3$

Putting value of length and finding volume:

$Volume\,\,of\,\,cube=length^3\\Volume\,\,of\,\,cube=(\frac{2}{5})^3\\ Volume\,\,of\,\,cube=\frac{8}{125}\,\,cm^3$

So, Volume of cube is $\frac{8}{125}\,\,cm^3$

Part c)

Volume of cube with side length of $\frac{1}{5}\,\,cm$

The formula used to find Volume of cube is:

$Volume\,\,of\,\,cube=length^3$

Putting value of length and finding volume:

$Volume\,\,of\,\,cube=length^3\\Volume\,\,of\,\,cube=(\frac{1}{5})^3\\ Volume\,\,of\,\,cube=\frac{1}{125}\,\,cm^3$

So, Volume of cube is $\frac{1}{125}\,\,cm^3$

Part d)

Volume of rectangular prism with

length= $\frac{1}{5}\,\,cm$

width= $\frac{2}{5}\,\,cm$

height = $\frac{3}{5}\,\,cm$

The formula used to find Volume of rectangular prism is:

$Volume\,\,of\,\,rectangular\,\,prism=length*width*height$

Putting values:

$Volume\,\,of\,\,rectangular\,\,prism=\frac{1}{5} *\frac{2}{5} *\frac{3}{5}\\Volume\,\,of\,\,rectangular\,\,prism=\frac{6}{125}\,\,cm^3$

So, Volume of Rectangular prism is $\frac{6}{125}\,\,cm^3$

Keywords: Volume

Learn more about Volume at:

#learnwithBrainly

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3 years ago