Answer:
Total paper required = 165 cm²
Step-by-step explanation:
Paper required to cover the entire block = (Surface area of the prism at the base - area of the top of the prism) + Lateral surface area of the pyramid
Surface area of the rectangular prism = 2(lb + bh + hl)
(here l, b, h are the length, width and height respectively)
= 2(5×5 + 5×4 + 4×5)
= 2(25 + 20 + 20)
= 2×65
= 130 cm²
Area of the top of the prism = (side)²
= 5²
= 25 cm²
Lateral area of the square pyramid = 4 × Area of one lateral side
= 4 × ![[\frac{1}{2}(\text{Base})(\text{Height})]](https://tex.z-dn.net/?f=%5B%5Cfrac%7B1%7D%7B2%7D%28%5Ctext%7BBase%7D%29%28%5Ctext%7BHeight%7D%29%5D)
= 4 × ![[\frac{1}{2}(5)(6)]](https://tex.z-dn.net/?f=%5B%5Cfrac%7B1%7D%7B2%7D%285%29%286%29%5D)
= 60 cm²
Total paper required = (130 - 25) + 60
= 105 + 60
= 165 cm²
I believe it 4004 mins i need to check up on it but im 95% positive its that
Answer:
2 minutes
Step-by-step explanation:
When you double the speed, the time needed to finish the lap would halve.
6 *2 =12
4/2 =2
A2 + b2 = c2
Number 1 is 15.1986.... or 15.2
Explanation: 5 squared is 25 and 16 squared is 256. Subtract 256 minus 25 to get 231, then divide it by the square root.
Number 2 is 7.21111.... or 7.2
Explanation: 6 squared plus 4 squared is 52, square root of 52= 7.2