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2 years ago

Last year 15 programs in her collection now she has 18 records what is the percent increase of her collection

Mathematics

1 answer:

laiz [17]2 years ago

7 0

Answer: 20%

Step-by-step explanation:

Last year she had 15 records and this year she has 18.

Difference is:

= 18 - 15

= 3

Percentage increase:

= 3/15

= 20%

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Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre

fenix001 [56]

Answer:

x^6y^3

Step-by-step explanation:

Given polynomial:

8x^6y^5 - 3x^8y^3

Get prime factors:

2*2*2*x*x*x*x*x*x*y*y*y*y*y - 3*x*x*x*x*x*x*x*x*y*y*y

Common factors of the two terms:

x*x*x*x*x*x*y*y*y = x^6y^3

So

x^6y^3(8y^2 - 3x^2)

x^6y^3 is the GCF of this polynomial

4 0

2 years ago

At which of the following points do the two equations f(x)=3x2+5 and g(x)=4x+4 intersect?

Basile [38]

Answer:

( $\frac{1}{3}$ , $\frac{16}{3}$ ) and (1, 8 )

Step-by-step explanation:

To find the points of intersection equate f(x) and g(x), that is

3x² + 5 = 4x + 4 ( subtract 4x + 4 from both sides )

3x² - 4x + 1 = 0 ← in standard form

(3x - 1)(x - 1) = 0 ← in factored form

Equate each factor to zero and solve for x

3x - 1 = 0 ⇒ 3x = 1 ⇒ x = $\frac{1}{3}$

x - 1 = 0 ⇒ x = 1

Substitute these values into either of the 2 functions for corresponding y- coordinates.

Substituting into g(x), then

g(1) = 4(1) + 4 = 4 + 4 = 8 ⇒ (1, 8 )

g( $\frac{1}{3}$ ) = $\frac{4}{3}$ + 4 = $\frac{16}{3}$ ⇒ ( $\frac{1}{3}$ , $\frac{16}{3}$ )

3 0

3 years ago

How do i solve that question?

yawa3891 [41]

a) The solution of this ordinary differential equation is $y =\sqrt[3]{-\frac{2}{\frac{3\cdot t}{8}-\frac{\sin 2t}{4}+\frac{\sin 4t}{32}-2 } }$ .

b) The integrating factor for the ordinary differential equation is $-\frac{1}{x}$ .

The particular solution of the ordinary differential equation is $y = \frac{x^{3}}{2}+x^{2}-\frac{5}{2}$ .

<h3>How to solve ordinary differential equations</h3>

a) In this case we need to separate each variable ( $y, t$ ) in each side of the identity:

$6\cdot \frac{dy}{dt} = y^{4}\cdot \sin^{4} t$ (1)

$6\int {\frac{dy}{y^{4}} } = \int {\sin^{4}t} \, dt + C$

Where $C$ is the integration constant.

By table of integrals we find the solution for each integral:

$-\frac{2}{y^{3}} = \frac{3\cdot t}{8}-\frac{\sin 2t}{4}+\frac{\sin 4t}{32} + C$

If we know that $x = 0$ and $y = 1$ , then the integration constant is $C = -2$ .

The solution of this ordinary differential equation is $y =\sqrt[3]{-\frac{2}{\frac{3\cdot t}{8}-\frac{\sin 2t}{4}+\frac{\sin 4t}{32}-2 } }$ . $\blacksquare$