Question

What is the exact distance from (−1, 4) to (6, −2)?

Answer 1

Same as last time:

d^2=(x2-x1)^2+(y2-y1)^2

d^2=(6--1)^2+(-2-4)^2

d^2=7^2+(-6)^2

d^2=49+36

d^2=85

d=√85  (85=5*7 and both 5 and 7 are prime so √85 cannot be simplified any further)

The exact distance is √85 units.  

Answer 2

Answer:

The distance is √ 85 units

Step-by-step explanation:

To find the exact value, all we will simply do is to use the distance formula to solve;

D =√ (x₂ - x₁)²  +  (y₂ - y₁)²

From the question given;

The points given are  (−1, 4)  and (6, −2)

so;   x₁  = -1         y₁ = 4      x₂ = 6      y₂ = -2

We can now proceed to substitute the formula into the equation

D = √ (x₂ - x₁)²  +  (y₂ - y₁)²

    =√ (6 - -1)²  +  (-2 - 4)²

    =√ (6+ 1)²  +  (-2 - 4)²

    =√ (7)²  +  (-6)²

    =√ 49  +  36

    =√ 85

     The distance is √ 85 units