Please help me with this. thank you!
2 answers:
Answer:
Step-by-step explanation:
Let's use the two noted points for the calculation of slope:
Point 1: (2,8) and
Point 2: (6,4)
These become our (x1,y1) and (x2,y2).
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We are trying to find a straight line equation of the form y = mx+b, where m is the slope and b is the y-intercept (the value of y when x = 0).
The slope:
m = (y2 - y1)/(x2 - x1)
m = (4 - 8)/(6 - 2)
m = -4/4
m = -1
This gives us y = -1x + b
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Find b by entering either of the two given points. I'll use (6,4):
y = -1x + b
4 = -1(6) + b
b = 10
The equation is now y = -x + 10
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Find the value of y when x = 9:
y = -x + 10
y(9) = -(9) + 10
y(9) = 1
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This graph has a negative trend. Y decreases as x increases. It crosses the y axis at 10 when x is 0, and is only positive when x < 10. See the attached graph. Note that the graph of this line does not intersect many of the points on the original graph. They fall to either side, and are not consistent with a single line equation. The general, negative trend of slope - 1 trend holds true, however, so one might conclude errors may have been made in collecting the data. That is clearly due to your lab partner. [Well, you might try a better explanation]. A craftier person might calculate a standard deviation of error for the line, but that's next semester. It is worthwhile noting that a selection of two points other than the ones chosen above for calculating slope, would result in different equations. We selected the two points used here ((2,8) and (6,4)) because they are clearly noted on the chart.
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The reflection of BC over I is shown below.
<h3>What is reflection?</h3>- A reflection is a mapping from a Euclidean space to itself that is an isometry with a hyperplane as a set of fixed points; this set is known as the reflection's axis (in dimension 2) or plane (in dimension 3).
- A figure's mirror image in the axis or plane of reflection is its image by reflection.
See the attached figure for a better explanation:
1. By the unique line postulate, you can draw only one line segment: BC
- Since only one line can be drawn between two distinct points.
2. Using the definition of reflection, reflect BC over l.
- To find the line segment which reflects BC over l, we will use the definition of reflection.
3. By the definition of reflection, C is the image of itself and A is the image of B.
- Definition of reflection says the figure about a line is transformed to form the mirror image.
- Now, the CD is the perpendicular bisector of AB so A and B are equidistant from D forming a mirror image of each other.
4. Since reflections preserve length, AC = BC
- In Reflection the figure is transformed to form a mirror image.
- Hence the length will be preserved in case of reflection.
Therefore, the reflection of BC over I is shown.
Know more about reflection here:
#SPJ4
The question you are looking for is here:
C is a point on the perpendicular bisector, l, of AB. Prove: AC = BC Use the drop-down menus to complete the proof. By the unique line postulate, you can draw only one segment, Using the definition of, reflect BC over l. By the definition of reflection, C is the image of itself and is the image of B. Since reflections preserve , AC = BC.
