The mercury (Hg) has 80 electrons. The electrons are distributed in the s, p, d and f orbitals. The electronic configuration of Hg can be shown as-
. We can see that there are two filled d-orbitals 3d and 4d. There is only one filled f orbital which is 4f. The electron cloud of the s, p, d and f are different due to their different screening and penetration effect towards the nucleus. The electron cloud of f-orbital is most diffuse than the other three. The outermost electrons of mercury is
, which is its valence electrons i.e. (+2).
The scenario that involves a reaction that is an equilibrium would be A. The chemical reaction is producing reactants and products at an equal rate.
Answer:
a. -7.44 °C
Explanation:
Hello there!
In this case, since the freezing point depression formula is:
![\Delta T_f=-i*m*Kf](https://tex.z-dn.net/?f=%5CDelta%20T_f%3D-i%2Am%2AKf)
Thus, since the Van't Hoff's factor is 2 for KCl as it ionizes in K⁺ and Cl⁻, the molarity is 2.0 m (2.0mol/1.0kg) and the freezing point depression constant is 1.86 °C/m, we calculate the freezing point depression as follows:
![\Delta T_f=-2*2.0m*1.86\°C /m\\\\\Delta T_f=-7.44\°C](https://tex.z-dn.net/?f=%5CDelta%20T_f%3D-2%2A2.0m%2A1.86%5C%C2%B0C%20%2Fm%5C%5C%5C%5C%5CDelta%20T_f%3D-7.44%5C%C2%B0C)
Therefore, the answer is a. -7.44 °C.
Regards!
Answer:
Metallic bonds is the answer!!