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jok3333 [9.3K]
4 years ago
13

What are your thoughts abt love and relationships?

Chemistry
1 answer:
kompoz [17]4 years ago
6 0

In my opinion most of the relationships are a lie,cheat,painful.

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If you made a three-dimensional model of an atom and its nucleus, how would you represent the atom? 7th grade
Gemiola [76]

Answer:

it shows the breakdown of the atom

Explanation:

it will show it molecularly

7 0
3 years ago
A certain radioactive isotope placed near a Geiger counter registers 160 counts per second. 32 hours later, the counter register
stealth61 [152]
I believe that the answer for this question would be option A. 8 HOURS. Based on the given scenario above about a certain radioactive isotope placed near a Geiger counter, the half-life <span>of the isotope 32 hours later would be 8 hours. Hope this is the answer that you are looking for. </span>
7 0
3 years ago
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Which highway run through comlumbus
Alexeev081 [22]

Answer:

Highway 22 ,GA 31820

Explanation:

3 0
3 years ago
What is the product of the unbalanced equation below?
inessss [21]

Answer:

C. HCI(g)

Explanation:

The following equation between hydrogen gas (H2) and oxygen gas (O2) is given below:

H2(g) + Cl2(g) ►

Based on these unbalanced equation, the products of the reaction was not given, however, if one molecule of hydrogen and oxygen combine, hydrogen chloride (HCl) should be produced as the product of the reaction as in:

H2(g) + Cl2(9) ► 2HCl(g)

4 0
3 years ago
What volume of 1.00 m hcl in liters is needed to react completely (with nothing left over) with 0.750 l of 0.100 m na2co3?
kotykmax [81]
The balanced equation for the reaction is as follows
Na₂CO₃ + 2HCl --> 2NaCl + CO₂ + H₂O
stoichiometry of Na₂CO₃ to HCl is 1:2
number of Na₂CO₃ moles reacted = molarity x volume
number of Na₂CO₃ moles = 0.100 mol/L x 0.750 L = 0.0750 mol 
according to molar ratio of 1:2
1 mol of Na₂CO₃ reacts with 2 mol of HCl
then 0.0750 mol of Na₂CO₃ mol reacts with - 2 x 0.0750 = 0.150 mol 
molarity of given HCl solution is 1.00 mol/L
molarity is defined as the number of moles of solute in 1 L of solution 
there are 1.00 mol in 1 L of solution 
therefore there are 0.150 mol in - 0.150 mol / 1.00 mol/L = 0.150 L 
volume of HCl required is 0.150 L 
3 0
3 years ago
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