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4 years ago

What are your thoughts abt love and relationships?

Chemistry

1 answer:

kompoz [17]4 years ago

6 0

In my opinion most of the relationships are a lie,cheat,painful.

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What is the [H+] of a solution with a pH of 6.6? Use a scientific calculator.

svetoff [14.1K]

8.3 × 106 - trust me, it's actually right. You can use the calculator to see if I'm correct. Punch in 8.3 × 106 = 6.6

7 0

4 years ago

Read 2 more answers

One-step constrained-volume synthesis of silver decorated polymer colloids with antimicrobial and sensing properties,

Anarel [89]

It would be the thurd

5 0

3 years ago

Balance the following skeleton reaction and identify the oxidizing and reducing agents: Include the states of all reactants and

rusak2 [61]

Answer:

$4Zn_(_s_)~+~7OH^-~_(_a_q_)~+~NO_3^-_(_a_q_)~+~6H_2O_(_l_)~-->4Zn(OH)_4^-^2_(_a_q_)~+~NH_3_(_g_)$

-) Oxidizing agent: $NO_3^-_(_a_q_)$

-) Reducing agent: $Zn_(_s_)$

Explanation:

The first step is separate the reaction into the semireactions:

A. $Zn~->Zn(OH)_4^-^2$

B. $NO_3^-~->~NH_3$

If we want to balance in basic medium we have to follow the rules:

1. We adjust the oxygen with $OH^-$

2. We adjust the H with $H_2O$

3. We adjust the charge with $e^-$

Lets balance the first semireaction A. :

$Zn~+~4OH^-~->Zn(OH)_4^-^2~+~2e^-$

Now, lets balance semireaction B:

$NO_3^-~+~8e^-~+~6H_2O~->~NH_3~+~9OH^-$

Finally, we have to add the two semireactions:

_________________________________________

$8~(Zn~+~4OH^-~->Zn(OH)_4^-^2~+~2e^-)$

$2~(NO_3^-~+~8e^-~+~6H_2O~->~NH_3~+~9OH^-)$

_________________________________________

$(8Zn~+~32OH^-~->8Zn(OH)_4^-^2~+~16e^-)$

$(2NO_3^-~+~16e^-~+~12H_2O~->~2NH_3~+~18OH^-)$

Cancel out the species on both sides:

$8Zn~+~14OH^-~+~2NO_3^-~+~12H_2O~-->8Zn(OH)_4^-^2~+~2NH_3$

Simplifying the equation :

$4Zn~+~7OH^-~+~NO_3^-~+~6H_2O~-->4Zn(OH)_4^-^2~+~NH_3$

The $Zn_(_s_)$ is oxidized therefefore is the reducing agent. The $NO_3^-_(_a_q_)$ is reduced therefore is the oxidizing agent.

4 0

4 years ago

What are three examples of organic matter in soil

Alborosie

Answer:

Bacteria, fungi and nematodes

5 0

3 years ago

Read 2 more answers

Consider the balanced equation for the following reaction:

wel

Answer:

The amount of ammonia needed is 33.3 g

Therefore, we can also say 1.96 moles of NH₃

Explanation:

The reaction is: 3CuO(s) + 2NH₃(g) → 3H₂O(l) + 3Cu(s) + N₂(g)

If we see stoichiometry, 3 moles of water can be produced by 2 moles of NH₃. We propose this rule of three:

3 moles of water can be produced by 2 mole of ammonia

Then, 2.94 moles of water, must be produced by (2.94 . 2) /3 =1.96 moles of NH₃

If we convert the moles to mass. 1.96 mol . 17 g /1mol = 33.3 g

4 0

4 years ago